使用 Python 写入 Excel 中的精确单元格

Question

非常感谢您的帮助！这是我现在的代码：我只需要触发一次，所以 1 次迭代，这是解决方案吗？ B 列留出一个空位，然后添加“2”。可能是因为它看的是索引：

import pandas as pd
from pathlib import Path

data_folder = Path(PATH)

file_to_open = data_folder / "excelbestand.xlsx"

df = pd.read_excel(file_to_open)

data_x = 4
data_y = 2

  
df.loc[df.index.max()+1, ['A']] = data_x

df.loc[df.index.max()+1,['B']] = data_y

df.to_excel(file_to_open, index = False)

Answer 1

首先，您似乎首先需要读取 pandas 中的数据框：

import pandas as pd

df = pandas.read_excel("name_your_file.xlsx",sheet_name = 'name_your_sheet')
num_iterations = 10 # Number of times you want to perform action
while i <= num_iterations:
    data_x = df['A'].count()
    df.loc[df.index.max()+1] = [data_x]

Answer 2

如您所见，pd.iloc 非常强大：df.iloc[ 行号，列号]： columns : A,B,C,D 列号 = 0,1,2,3

import pandas as pd
from pathlib import Path

data_folder = Path(PATH)

file_to_open = data_folder / "excelbestand.xlsx"

df = pd.read_excel(file_to_open)

num_iterations = 1
data_x = 4
i=0
##### In this while you are appending the count of column "A" to the end of column "A"

while i <= num_iterations:   
    df.loc[df.index.max()+1, 0] = [data_x]
    i += 1
###########code for adding to las cell of column B 
i2 = 0    
while i2 <= num_iterations:
    df.loc[df.index.max()+1,1] = [data_x]
    i += 1

df.to_excel(file_to_open, index = False)