如何将 BMI 计算添加到以下代码中？

Question

下面是我的代码：

def inForm():
  name = requestString("What is your name?")
  age = requestInteger("What is your age?")
  height = requestInteger("What is your height?")
  weight = requestInteger("What is your weight?")
  print "Hello", name, "!", "You are", age,"years old!", "Your height  
  is", height, "cm", "and you weigh", weight, "kg"

我需要在这段代码中添加 BMI 计算，这是我的公式，BMI =weight/(height*height)

根据 BMI 显示这些消息：

你的体重严重不足，不到 15 岁

您从 15.0 到 16.0 体重严重不足

您从 16.0 到 18.5 体重过轻

你的体重在 18.5 到 25 之间是正常的

你从 25 岁到 30 岁超重

您在 30 到 35 岁之间属于中度肥胖

你从 35 岁到 40 岁严重肥胖

你 40 岁以上严重肥胖

我似乎无法弄清楚，我该怎么做？

提前致谢！

Answer 1

与其将 cm 转换为 m，不如使用 requestNumber 作为身高和体重。此外，打印语句可能会更短，就像我在下面演示的那样。另外，我使用 %s %d %r 这称为String Formatting Operations。

def inForm():
 name = requestString("Please enter your name")
 age = requestInteger("How old are you?")
 height = requestNumber("How tall are you? (Meters)")
 weight = requestNumber("How heavy are you? (Kilograms)")
 bmi = weight/(height*height)

 print "Hello, %s! I see that you are %r years old, %r meters tall, weight %r kgs and your BMI is %d." % (name, age, height, weight, bmi)

 n = bmi
 if n<15:
  print "You are very severely underweight"
 elif 15<=n<=16:
  print "You are severely underweight"
 elif 16<n<=18.5:
  print "You are underweight"
 elif 18.5<n<=25:
  print "Your weight is normal"
 elif 25<n<=30:
  print "You are overweight"
 elif 30<n<=35:
  print "You are moderately obese"
 elif 35<n<=40:
  print "You are severely obese"
 elif n>40:
  print "You are very severely obese"

Answer 2

在计算 bmi 时，您通常使用以米为单位的高度（而不是厘米）。这意味着您需要对公式中从 cm 到 m 的转换进行两次调整：

bmi = 10000 * weight / (height*height)
print bmi

您可以对文本部分使用 if-elif-...-else 语句：

if bmi < 15:
    message = "very severely underweight"
elif bmi <= 16:
    message = "severely underweight"
# Add more elif parts here...
else:
    message = "very severely obese"

print "You are", message