根据字母的对称性创建镜像词

【问题标题】：Creating a mirrored word based on symmetry of letter根据字母的对称性创建镜像词
【发布时间】：2016-10-26 15:21:03
【问题描述】：

我创建了这个程序，如果它是对称的，它应该显示一个单词的镜像。不幸的是，当我测试“TIMOTHY”时，它显示它无法镜像，我无法弄清楚为什么这不起作用。

#Program for creating a mirrored
#image word#
def main():

    mirrors = ["A","H","I","M","O","T","U","V","W","X","Y"
               "b","d","i","l","m","o","p","t","v","w","x"]

    word = input("Enter in the word you'd like mirrored: ")

    for x in word:
        if x not in mirrors:
            y = True
            break

    if y == True:
        print("Sorry your word can not be mirrored")


    wordlist = ''.join(word[i] for i in range(len(word) -1, -1, -1 ))

    print(wordlist)




main()

【问题讨论】：

标签： python string list-comparison

【解决方案1】：

mirrors = ["A","H","I","M","O","T","U","V","W","X","Y"
               "b","d","i","l","m","o","p","t","v","w","x"]

这就是问题所在。 “b”跟在“Y”后面，中间没有逗号。 Python 的一个鲜为人知的怪癖是两个相邻的字符串文字将自动连接。所以“Y”和“b”都不在你的列表中，但“Yb”在。

要解决此问题，请添加逗号。

mirrors = ["A","H","I","M","O","T","U","V","W","X","Y",
               "b","d","i","l","m","o","p","t","v","w","x"]

此外，如果您不想稍后在if y == True 块期间获得UnboundLocalError，则应该在循环之前执行y = False。

【讨论】：