如何修复方法错误

Question

我只是想确保我在这里是正确的。我正在尝试将方法添加到

• 改变高度
• 改变宽度
• 更改坐标
• 计算周长

• 计算面积

  public class MyRectangle {
  
  public int width;
  public int height;
  public int y;
  public int x;
  
  public MyRectangle()
  {
      width=10;
      height=10;
      y=10;
      x=10;
  
  public int MyRectangle;
  
  public MyRectangle(int width, int height, int y, int x, int MyRectangle) {
      this.width = width;
      this.height = height;
      this.y = y;
      this.x = x;
      this.MyRectangle = MyRectangle;
  }
  }
  

而且我的方法也出现了非法的表达式开始错误。

Answer 1

这是你的问题，方法中不能有方法。 但这是由于您没有为您的方法关闭括号。 我修复了您的代码并添加了您想要的方法：

public class MyRectangle {

    //Best to group your variables up here
    public int MyRectangle;
    public int width;
    public int height;
    public int y;
    public int x;

    public MyRectangle() {
        width  = 10;
        height = 10;
        y      = 10;
        x      = 10;
    }//Make sure to close this method with the bracket

    public MyRectangle(int width, int height, int y, int x, int MyRectangle) {
        this.width = width;
        this.height = height;
        this.y = y;
        this.x = x;
        this.MyRectangle = MyRectangle;
    }

    /**
     * Changes the current height to the given new height
     * @param newHeight
     */
    public final void changeHeight(int newHeight) {
        height = newHeight;
    }

    /**
     * Changes the current width to the given new width
     * @param newWidth
     */
    public final void changeWidth (int newWidth) {
        width = newWidth;
    }

    /**
     * Calculates the current perimeter based on the width and height
     * @return parameter ofd the rectangle
     */
    public final int getPerimeter() {
        return ((2 * width) + (2 * height));
    }

    /**
     * Calculates the area based on the width and height
     * @return area of the rectangle
     */
    public final int getArea() {
        return (width * height);
    }

    public final void changesXCoordinate(int newX){
        x = newX;
    }

    public final void changesYCoordinate(int newY){
        y = newY;
    }

    public final void changesCoordinate(int newX, int newY) {
        x = newX;
        y = newY;
    }
}

我会尽快解释，只是想先发布正确的代码：P

就目前而言，很难理解您还在寻找什么。

如果这是您要查找的内容，请将其标记为正确答案：D