【发布时间】:2016-07-08 10:00:16
【问题描述】:
我希望 click 方法只被调用一次,我该怎么做才能得到这个结果? 这是我的代码:
public override View GetView(int position, View convertView, ViewGroup parent)
{
View result = convertView;
if (result == null)
{
result = LayoutInflater.From(_Context).Inflate(Resource.Layout.DiagnoseTemplateLayout, null, false);
}
TextView textView = result.FindViewById<TextView>(Resource.Id.DiagnoseTemplateTextView);
textView.Text = _Diagnoses[position].Description;
Button button = result.FindViewById<Button>(Resource.Id.DeleteDiagnoseTemplateButton);
button.Tag = _Diagnoses[position].Key;
button.Click += delegate
{
if (_Diagnoses[position] != null)
{
AlertDialog.Builder builder = new AlertDialog.Builder(_Context);
builder.SetTitle("Varning");
builder.SetMessage("Delating selected item?");
builder.SetPositiveButton("YES", delegate
{
SuperBillAddActivity.SuperBill.Diagnoses.Remove(_Diagnoses[position]);
SuperBillAddActivity.RefreshLists();
});
builder.SetNegativeButton("NO", delegate { });
builder.Show();
}
};
return result;
}
这个方法被调用了 3 次 button.Click += delegate 从我们点击按钮的位置开始
public override View GetView(int position, View convertView, ViewGroup parent)
{
View result = convertView;
if (result == null)
{
result = LayoutInflater.From(_Context).Inflate(Resource.Layout.DiagnoseTemplateLayout, null, false);
}
TextView textView = result.FindViewById<TextView>(Resource.Id.DiagnoseTemplateTextView);
textView.Text = _Diagnoses[position].Description;
Button button = result.FindViewById<Button>(Resource.Id.DeleteDiagnoseTemplateButton);
button.Tag = _Diagnoses[position].Key;
button.Click += delegate
{
if ((_Clicked) && (_Diagnoses[position] != null))
{
_Clicked = !_Clicked;
AlertDialog.Builder builder = new AlertDialog.Builder(_Context);
builder.SetTitle("Varning");
builder.SetMessage("Delating selected item?");
builder.SetPositiveButton("YES", delegate
{
_Clicked = !_Clicked;
SuperBillAddActivity.SuperBill.Diagnoses.Remove(_Diagnoses[position]);
SuperBillAddActivity.RefreshLists();
});
builder.SetNegativeButton("NO", delegate
{
_Clicked = !_Clicked;
});
builder.Show();
}
};
return result;
}
_Clicked
【问题讨论】:
-
我下面的回答对您有帮助,您可以将其标记为正确吗?我很感激。
标签: android methods xamarin getview