在 Laravel 与搜索中选择选项

Question

它在 laravel 中。我想搜索然后选择 mysql 表中的数据。目前我正在使用选择选项下拉菜单。该列表最终将不合理地长时间使用。所以我想输入单词，然后它会给我选项。在我的数据库表中，我有团队名称电子邮件地址和邮政编码。

    <div id="team_model" class="modal" tabindex="-1" role="dialog">
<div class="modal-dialog" role="document">
    <div class="modal-content">
        <div class="modal-header">
            <h5 class="modal-title">Modal title</h5>
            <button type="button" class="close" data-dismiss="modal" aria-label="Close">
                <span aria-hidden="true">&times;</span>
            </button>
        </div>
        <form method="post" action="{{url("athlete/request_for_team_sibling")}}" enctype="multipart/form-data">
            {{ csrf_field() }}
            <div class="modal-body">

                <input type="hidden" name="id" id="teamuserid"  value=''>

                <select class="form-control form-control-sm teamselect" id="teamselect" required name="team_id">
                    <option value="" disabled selected>Select Team</option>
                    @foreach($teams as $team)
                        <option value="{{$team->id}}">{{$team->name}}&nbsp;{{$team->address}}&nbsp;{{$team->city}}&nbsp;{{$team->state}}&nbsp;{{$team->zipcode}}</option>
                    @endforeach
                </select>
            </div>
            <div class="modal-footer">
                <button type="submit"  class="btn btn-primary saveteam">Save</button>
                <input type="button" class="btn btn-secondary" data-dismiss="modal" value="Close">
            </div>
        </form>

Answer 1

 $Teams = Team::where('name', 'LIKE', '%' . $request['team_id'] . '%')
      ->orWhere('email', 'LIKE', '%' . $request['team_id']  . '%')
      ->orWhere('address', 'LIKE', '%' . $request['team_id']  . '%')
      ->orWhere('zipcode', 'LIKE', '%' . $request['team_id']  . '%')
      ->get();