【发布时间】:2015-05-24 20:32:05
【问题描述】:
我在 Python 3 中有这样的 txt 文件(城市只是示例):
Tokyo 0 267 308 211 156 152 216 27 60 70 75
London 267 0 155 314 111 203 101 258 254 199 310
Paris 308 155 0 429 152 315 216 330 295 249 351
Vienna 211 314 429 0 299 116 212 184 271 265 252
Tallinn 156 111 152 299 0 183 129 178 143 97 199
Helsinki 152 203 313 116 183 0 99 126 212 151 193
Stockholm 216 101 216 212 129 99 0 189 252 161 257
Moscow 27 258 330 184 178 126 189 0 87 73 68
Riga 60 254 295 271 143 212 252 87 0 91 71
Melbourne 70 199 249 265 97 151 161 73 91 0 128
Oslo 75 310 351 252 199 193 257 68 71 128 0
我想通过一个例子让程序像这样工作:
Please enter starting point: Paris
Now please enter ending point: Riga
Distance between Paris and Riga is 295 km.
我是 Python 的新手,我不知道如何读取列表中的距离列表。 到目前为止,我设法做到了:
cities = []
distances = []
file = open("cities.txt")
for city_info in file:
city_info = city_info.strip()
city = city_info.split()
cities.append(city[0])
distances2 = []
for dist in city[1:]:
distances2.append(int(dist))
distances.append(distances2)
# to check, if lists are good to go
print(distances)
print(cities)
file.close()
amount = len(cities)
for x in range(amount):
for y in range(amount):
startpoint = cities[x]
endpoint = cities[y]
dist1 = distances[x][y]
startpoint = input("Enter start point: ").capitalize()
if startpoint not in cities:
print("Start point doesn't exist in our database: ", startpoint)
else:
endpoint = input("Enter end point: ").capitalize()
if endpoint not in cities:
print("Start point doesn't exist in our database: ", endpoint)
else:
print("Distance between", startpoint, "and", endpoint, "is", dist1, "kilometers.")
由于我对 Python 语言不是很精通,所以我不知道自己做错了什么。
例如我想得到城市[1]和城市[4]之间的距离,所以它应该从距离[1][4]中找到距离。
【问题讨论】:
-
你的缩进不正确...
-
在代码中的许多坏事中,最引人注目的是嵌套 for 循环之后的缩进,它应该与内部 for 处于同一级别。
标签: python list python-3.x