递归函数在开发结束时给出 500 错误

Question

我有一个相当困难的错误。以下函数是一个递归脚本，旨在检索导航层。

//递归函数设置更高 级别导航树
函数子级别 ($part_tree) {
// print_r($part_tree);

//set new layer if initive
if (empty ($part_tree['tree_name'])) {
  $grandchild_array = explode ("|", $part_tree['children'][0]);

T //用新层的正确子代填充主数组 foreach ($grandchild_array as $key => $array) { if (is_array($array)) {

    foreach ($array as $inner_key => $current_id) {
      $result = mysql_query("SELECT children FROM

".PRE."导航 WHERE id = '$current_id'");

      $row = mysql_fetch_array($result);

      $new_child[$current_id] = $row['children'];
    }

    foreach ($new_child as $new_id => $row) {

        $part_tree['children'][$new_id] = $row['children'];

      }

  } else {
  // echo $array;
   $result = mysql_query("SELECT children FROM ".PRE."navigation WHERE

id = '$array'");

   $row = mysql_fetch_array($result);

   $part_tree['children'][$array] = $row['children'];

  }
  }

}

//创建当前层

foreach ($part_tree['children'] as $key => $child_string) {

if (!empty ($child_string)) {
$temp_array = explode ("|", $child_string);
$part_tree['children'][$key] = $temp_array;
}   }

//查看是否需要新层 每个孩子 foreach ($part_tree['children'] as $key => $array) {

if (!empty ($array)) {
  $temp_string = implode ("|", $array);
  $part_tree['children'][$key]['children'][]

= $temp_string; $part_tree = $this -> subLevels ($part_tree['children'][$key]);

}

}

返回 $part_tree;

 }//function

我相当有信心这是有问题的部分

//如果是初始层，则设置新层 如果（空（$part_tree['tree_name']））{ $grandchild_array = explode("|", $part_tree['children'][0]);

  //populate the main array with the correct children for the new layer
  foreach ($grandchild_array as $key => $array) {
  if (is_array($array)) {

    foreach ($array as $inner_key => $current_id) {
      $result = mysql_query("SELECT children FROM

".PRE."导航 WHERE id = '$current_id'"); $row = mysql_fetch_array($result); $new_child[$current_id] = $row['children']; }

    foreach ($new_child as $new_id => $row) {
        $part_tree['children'][$new_id] =

$row['孩子']; }

  } else {
  // echo $array;
   $result = mysql_query("SELECT children FROM ".PRE."navigation WHERE

id = '$array'"); $row = mysql_fetch_array($result);

   $part_tree['children'][$array] = $row['children'];

  }
  }

}

问题的本质是：当我完成上述部分后，服务器开始返回错误 500。具体来说，一旦我完成了填充 $part_tree['children'][$variable_name] 的代码，我立即点击问题。

只有使用该数组元素集，该函数的其余部分才能工作。在第一次迭代中，它以正确的格式提供，并在此处为每个后续导航层重新填充。

我唯一想到的解决方案是我回避太深，服务器不喜欢它。我减少了导航表，因此任何给定的根级别最多导致其他 3 个，这意味着该函数运行 3 次，但这并没有成功。在此之前，我一直在测试无限制的递归问题。

如果有人可以为这个 500 错误提供替代原因，我会全力以赴。

激活错误标记后，站点返回以下消息：

Notice: Undefined index: expire in /mnt/sw/2028751/web_applications/web/project_site/secure_includes/modules/users/index.php on line 32
Notice: Undefined property: user::$logged in /mnt/sw/2028751/web_applications/web/project_site/secure_includes/modules/users/class.php on line 153
Notice: Undefined property: user::$logged in /mnt/sw/2028751/web_applications/web/project_site/secure_includes/modules/users/class.php on line 153
Notice: Undefined index: expire_flag in /mnt/sw/2028751/web_applications/web/project_site/secure_includes/modules/preprocessor/index.php on line 29
Notice: Undefined variable: error404 in /mnt/sw/2028751/web_applications/web/project_site/secure_includes/modules/preprocessor/index.php on line 36

这个一遍又一遍：

Notice: Array to string conversion in /mnt/sw/2028751/web_applications/web/project_site/secure_includes/modules/navigation/class.php on line 91

我觉得这很奇怪，因为我一直在处理的唯一文件是 navigation/class.php。

Answer 1

首先您可以尝试使用以下 PHP 代码启用错误报告：

ini_set('display_errors','On'); 
error_reporting(E_ALL); 

我记得 a previous question 这似乎很有帮助。

这可以帮助缩小范围或指定根本原因（或者在某些情况下，一起解决）。 让我知道情况如何，我会继续提供帮助。