【发布时间】:2015-08-25 15:14:33
【问题描述】:
我正在开发一个安卓应用程序。该应用在 Listview 中使用 json 和 ListAdpter 绑定数据。现在我想根据用户在搜索框中写信来过滤这些数据。我试图这样做,但由于列表视图中绑定了多个数据,我不知道如何过滤它。以下是我的代码:
private void getdatalatlog(double latitude, double longitude) {
// TODO Auto-generated method stub
//value=5;
String url = "http://bizzcoder.co.in/php/comments.php?latitude='"+latitude+"'&longitude='"+longitude+"'&value='"+value+"'";
aq.progress(R.id.progressBar1).ajax(url, JSONObject.class, this,"jsonCallback");
}
public void jsonCallback(String url, JSONObject json, AjaxStatus status) {
if (json != null) {
List<String> city = new ArrayList<String>();
mCommentList = new ArrayList<HashMap<String, String>>();
Gson gson = new GsonBuilder().create();
try {
JSONArray jsonResponse = json.getJSONArray("posts");
city = gson.fromJson(jsonResponse.toString(),List.class);
for (int i = 0; i < jsonResponse.length(); i++) {
JSONObject c = jsonResponse.getJSONObject(i);
String title = c.getString(TAG_TITLE);
String content = c.getString(TAG_MESSAGE);
String username = c.getString(TAG_USERNAME);
String lat = c.getString(TAG_LATITUDE);
String log = c.getString(TAG_LONGITUDE);
String cont = c.getString(TAG_CONTACT);
// creating new HashMap
HashMap<String, String> map = new HashMap<String, String>();
map.put(TAG_TITLE, title);
map.put(TAG_MESSAGE, content);
map.put(TAG_USERNAME, username);
map.put(TAG_LATITUDE, lat);
map.put(TAG_LONGITUDE, log);
map.put(TAG_CONTACT, cont);
// adding HashList to ArrayList
mCommentList.add(map);
}
}
catch (JSONException e) {
Toast.makeText(aq.getContext(), "Error in parsing JSON", Toast.LENGTH_LONG).show();
}
catch (Exception e) {
Toast.makeText(aq.getContext(), "Something went wrong", Toast.LENGTH_LONG).show();
}
ListAdapter adapter = new SimpleAdapter(this, mCommentList,
R.layout.single_post, new String[] { TAG_TITLE,TAG_USERNAME ,TAG_CONTACT ,TAG_MESSAGE ,TAG_LATITUDE , TAG_LONGITUDE
}, new int[] { R.id.shop_name,R.id.address,R.id.contact,R.id.distance,R.id.latitude,R.id.longitude });
setListAdapter(adapter);
/**
* Enabling Search Filter
* */
inputSearch.addTextChangedListener(new TextWatcher() {
@Override
public void onTextChanged(CharSequence cs, int arg1, int arg2, int arg3) {
// When user changed the Text
Shopdetail.this.adapter.getFilter().filter(cs);
}
@Override
public void beforeTextChanged(CharSequence arg0, int arg1, int arg2,
int arg3) {
// TODO Auto-generated method stub
}
@Override
public void afterTextChanged(Editable arg0) {
// TODO Auto-generated method stub
}
});
ListView lv = getListView();
lv.setOnItemClickListener(new OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> parent, View view,
int position, long id) {
Intent intent = new Intent();
Bundle b = new Bundle();
String name= ((TextView) view.findViewById(R.id.shop_name)).getText().toString()+" , "+((TextView) view.findViewById(R.id.contact)).getText().toString();
String lati= ((TextView) view.findViewById(R.id.latitude)).getText().toString();
String longi= ((TextView) view.findViewById(R.id.longitude)).getText().toString();
b.putString("shop",name);
b.putString("lati",lati);
b.putString("long",longi);
intent.setClass(Shopdetail.this, Mapview.class);
intent.putExtras(b);
startActivity(intent);
}
});
}
}
listview 中绑定了多个详细信息,例如商店名称、联系电话、地址等。我只想按商店名称过滤它。但我在 getfilter() 方法下面划了红线。
【问题讨论】:
标签: android listview android-listview listadapter