从多维数组构建 MySQL 插入语句答案

【问题标题】：Building MySQL insert statement from multidimensional array从多维数组构建 MySQL 插入语句
【发布时间】：2014-02-09 04:24:12
【问题描述】：

我需要从一个数组构建 INSERT 语句，但我被困住了，这是我目前所拥有的，但它显然是不正确的：

INSERT INTO company (, Name, Address, City, State, Zip, Country, Website, NOL
INSERT INTO additionallocations (, CompanyID, Address, City, State, Zip, Country

这是我的数组以及我如何构建语句：

$fieldsArray = array(
                    'company' => array(
                            'Name' => $Name,
                            'Address' => $Address,
                            'City' => $City,
                            'State' => $State,
                            'Zip' => $Zip,
                            'Country' => $Country,
                            'Website' => $Website,
                            'NOL' => $NOL,
                        ),
                    'additionallocations' => array(
                            'CompanyID' => $CompanyID,
                            'Address' => $Address,
                            'City' => $City,
                            'State' => $State,
                            'Zip' => $Zip,
                            'Country' => $Country,
                        )
                    );




        foreach($fieldsArray as $table => $rows) {
            $sql = "INSERT INTO " . $table . " (";
            foreach($rows as $column => $value){
                $sql .= ", " .$column;
            }
        }

        echo $sql;

这是我想要的结果：

INSERT INTO company (Name, Address, City, State, Zip, Country, Website, NOL) VALUES
                             ('$Name', '$Address', '$City', '$State', '$Zip', '$Country', '$Website', '$NOL');

我需要找到一种方法来继续使用 VALUES 构建它，并去掉左括号后的第一个逗号。有人有什么建议吗？

【问题讨论】：

你说你需要这个值，你的值将如何传递？
什么意思？我想在 VALUES 部分中使用变量名称，例如 INSERT INTO company (Name, Address, City, State, Zip, Country, Website, NOL) VALUES ('$Name', '$Address', '$City', '$State', '$Zip', '$Country', '$Website', '$NOL');

标签： php mysql arrays multidimensional-array

【解决方案1】：

foreach($fieldsArray as $table => $rows) 
{
    $sql = "INSERT INTO " . $table . "(";
    foreach($rows as $column => $value)
    {    
         $sql .= $column.", ";
    }
    $sql = rtrim($sql, ", ");
    $sql .= ") VALUES (";

    foreach($rows as $column => $value)
    {    
         $sql .= "'".$value."', ";
    }
    $sql = rtrim($sql, ", ");
    $sql .= ")";
    echo $sql; 
}

【讨论】：

rtrim($sql, ", "); 应该是$sql = rtrim($sql, ", ");

【解决方案2】：

我得到了它的工作：

foreach($fieldsArray as $key => $table){            
    $keys = array_keys($table);
        $values = null;
        $x = 1;

        foreach($keys as $value) {
            $values .= "?";
            if($x < count($keys)) {
                $values .= ', ';
            }
            $x++;
        }

    echo $sql = "INSERT INTO {$key} (`" . implode('`, `', $keys) . "`) VALUES ({$values})" . "<br/>";

}

【讨论】：