如果它们出现在子字符串中，则从列表中返回一个或多个值答案

【问题标题】：Return one or more values from a list if they appear in a substring如果它们出现在子字符串中，则从列表中返回一个或多个值
【发布时间】：2022-01-19 19:23:58
【问题描述】：

我有一个列表和一个字符串：

lst = ['rock','paper','scissor','green apple', 'red apple']

我想创建一个函数，如果它们在文本中显示为子字符串，则从列表中返回一串项目

例如：

lst = ['rock','paper','scissor','green apple', 'red apple']
def my_func(string):
        .
        .
        .
    return print(new_string)

#------------

string1 = 'we like rock and green apples' 
string2 = 'i wrote on paper'
string3 = 'we played rock, paper, scissors, and had apples'

my_func(string1)
my_func(string2)
my_func(string3)

rock, green apples
paper 
rock, paper, scissor

【问题讨论】：

标签： python list function substring

【解决方案1】：

给你！

lst = ['rock','paper','scissor','green apple', 'red apple']
def my_func(string):
    new_string = ''
    for i in lst:
        if i in string:
            new_string += i + ', '
    return print(new_string)

string1 = 'we like rock and green apples'
string2 = 'i wrote on paper'
string3 = 'we played rock, paper, scissors, and had apples'

my_func(string1)
my_func(string2)
my_func(string3)

【讨论】：

谢谢 :) 我会尽快接受答案
更改为 new_string += ('' if new_string == '' else ', ') + i 以删除悬空逗号