Python 3 石头剪刀布问题

Question

我正在为编程作业做一个石头、纸、剪刀游戏，但我遇到了一个小障碍。该程序假设由用户选择 4 个选项中的 1 个来运行，1) 岩石，2) 纸，3) 剪刀和 4) 退出。一旦玩家选择了一个选项，就会显示计算机选择并宣布获胜者，并且程序会询问您是否想玩另一个游戏。如果选择 y，您将返回主菜单选择另一个选项，其他任何内容都会显示赢、输的游戏数量以及以平局结束的游戏数量。如果玩家选择 4，程序应该会说“Exiting program...”，然后会显示游戏结果。

这是我的问题：

1. 一旦您做出第一次选择，就会显示获胜者，并且程序会返回主菜单。如果您进行第二次选择，它将通知您计算机选择了什么，然后询问您是否想再次播放。 Y 会带你回到主菜单，电脑选择永远不会改变，无论你选择什么，游戏总是会以与第一个游戏相同的结果结束。如果您选择不再玩，则会显示赢、输和平局的数量（这似乎运行正常）。

2. 退出选项将带您返回主菜单，而不是显示游戏结果。我不确定该 if 语句应该放在哪里。

对于这些问题的任何帮助将不胜感激。

谢谢

#import module
import random

def main():
    #create a variable to control the loop
    play_again = 'y'

    #create a counter for tied games, computer games and player games
    tied_games = 0
    computer_games = 0
    player_games = 0

    #display opening message
    print("Let's play rock, paper scissors!") 

    computer_choice = process_computer_choice()

    player_choice = process_player_choice()

    winner = determine_winner(player_choice, computer_choice)

    #setup while loop for playing multiple games
    while play_again == 'y' or play_again == 'Y':

        process_computer_choice()

        process_player_choice()

        #use a if else statement to print the computers choice
        if computer_choice == 1:
            print('computer chooses rock.')

        elif computer_choice == 2:
            print('computer chooses paper.')

        else:
            print('computer chooses scissors.')

            #call the determine winner function    
            determine_winner(player_choice, computer_choice)

        #check who won the game and add 1 to the correct counter
        if winner == 'computer':
            computer_games += 1

        elif winner == 'player':
            player_games += 1

        else:
            tied_games += 1

        #ask the user if they would like to play again    
        play_again = input('would you like to play again? (enter y for yes): ')

    #display number of games that were won by the computer, the player and that were tied
    print()
    print('there was', tied_games, 'tied games.')
    print('the player won', player_games, 'games.')
    print('The computer won', computer_games,'games.')

#define the process computer function
def process_computer_choice():

    #setup computer to select random integer between 1 and 3
    choice1 = random.randint(1, 3)

    #return the computers choice
    return choice1

#define the process player function
def process_player_choice():

    #add input for players choice
    print()
    print('        MENU')
    print('1) Rock!')
    print('2) Paper!')
    print('3) Scissors!')
    print('4) Quit')
    print()

    player_choice = int(input('Please make a selection:  '))

    #add if statement for quit option
    if player_choice == 4:
        print('Exiting program....')

   #validate if the user enters a correct selection
    while player_choice != 1 and player_choice != 2 and player_choice != 3 and player_choice != 4:

        #print a error message if the wrong selection is entered
        print('Error! Please enter a correct selection.')

        player_choice = int(input('Please make a selection: '))

    #return the players choice
    return player_choice

#define the determine winner function
def determine_winner(player_choice, computer_choice):

    #setup if else statements for each of the 3 computer selections
    if computer_choice == 1:
        if player_choice == 2:
            print('Paper wraps rock. You win!')
            winner = 'player'

        elif player_choice == 3:
            print('Rock smashes scissors. The computer wins!')
            winner = 'computer'

        else:
            print('The game is tied. Try again.')
            winner = 'tied'

    if computer_choice == 2:
        if player_choice == 1:
            print('Paper wraps rock. The computer wins!')
            winner = 'computer'

        elif player_choice == 3:
            print('Scissors cut paper. You win!')
            winner = 'player'

        else:
            print('The game is tied. Try again.')
            winner = 'tied'

    if computer_choice == 3:
        if player_choice == 1:
            print('Rock smashes scissors. You win!')
            winner = 'player'

        elif player_choice == 2:
            print('Scissors cut paper. The computer wins!')
            winner = 'computer'

        else:
            print('The game is tied. Try again.')
            winner = 'tied'

    return winner

main()

Answer 1

对于问题 1，这是因为您在循环之前设置了计算机和播放器选项，并且从未更新它们。将循环的开头更改为：

while play_again == 'y' or play_again == 'Y':
    computer_choice = process_computer_choice()
    player_choice = process_player_choice()

您还可以在循环之前删除检查输入和获胜者的代码行，因为它在第一轮的技术上是多余的。

对于问题 2，只需在选择 4 后添加结果，如下所示：

if player_choice == 4:
      print('Exiting program....')  
      print('there was', tied_games, 'tied games.')
      print('the player won', player_games, 'games.')
      print('The computer won', computer_games,'games.')
      sys.exit() # be sure you add 'import sys' to the beginning of your file

另外，主循环中的行determine_winner(player_choice, computer_choice) 是缩进的，因此只有在计算机选择剪刀时才会调用它，所以你应该取消缩进:)

Answer 2

您不是再次分配给computer_choice 或player_choice，而是使用它的值。

while play_again == 'y' or play_again == 'Y':

    process_computer_choice()

    process_player_choice()

应该是

while play_again == 'y' or play_again == 'Y':

    computer_choice = process_computer_choice()

    player_choice = process_player_choice()

至于退出只是在退出选择中休息。你必须尽早从 process_player_choice 中返回，并且在 main 中做一些事情。

所以在 process_player_choice 中：

if player_choice == 4:
    print('Exiting program....')
    return

主要是： player_choice = process_player_choice()

if player_choice == 4:
     return 

winner = determine_winner(player_choice, computer_choice)

#setup while loop for playing multiple games
while play_again == 'y' or play_again == 'Y':

    computer_choice = process_computer_choice()

    player_choice = process_player_choice()
    if player_choice == 4:
         break