在 node.js 中为 require 设置路径

Question

我有一个这样的文件夹结构。

• include/

  • index.js

  • plugin/

    • plugin.js
    • helper.js

地点：-

包含/index.js

//Function for mapping the path of  "require" statement in  the plugin.js file.

var mapRequirePath = function(){

    var plugins = require('./plugin/plugin');
     return plugins;
}

//Now call the plugins..
var plugin = mapRequirePath();

include/plugin/plugin.js

    /*
       I want all four require statements to point to the same file location '/include/plugin/helper.js'

      i.e search in the same folder location for module irrespective of the '../' or '../../' present in the require statement
    */

    var helper1 = require('./helper');
    var helper2 = require('helper');
    var helper3 = require('../../helper');
    var helper4 = require('../helper');

我想在plugin.js 文件中映射require 的路径，这样所有的require 调用都应该在same directory only 中搜索它的模块。

Answer 1

如果您想将 /foo/bar 添加到要求：

• 通过编辑 process.env.NODE_PATH

那么你的 js 文件应该位于 /foo/bar/node_modules/

process.env.NODE_PATH = '/foo/bar' + ':' + process.env.NODE_PATH;

• 通过编辑module.paths

那么你的 js 文件应该位于 /foo/bar/

module.paths.push('/foo/bar');

Answer 2

您也许可以动态更改 NODE_PATH 环境变量：

// First take a backup:
var _NODE_PATH = process.env.NODE_PATH;
// Add /includes/plugin to the path, also note that we need to support 
//   `require('../hello.js')`. We can do that by adding /includes/plugin/a, 
//   /includes/plugin/a/b, etc.. to the list
process.env.NODE_PATH+=':/includes/plugin:/includes/plugin/a';
// Do your think...
require('./plugins/plugin');
// Restore NODE_PATH 
process.env.NODE_PATH = _NODE_PATH;

Answer 3

尝试通过命令行更改 NODE_PATH 变量：

exports NODE_PATH=directoryYouWant

如果您不想为每个其他项目更改它，您可以尝试在 .js 文件中动态更改它：

var currentNodePath = process.env.NODE_PATH;
process.env.NODE_PATH = directoryYouWant;
//do stuff then change it back
process.env.NODE_PATH = currentNodePath;