获取调用者绝对路径 - Bash Mac OS X Leopard

Question

我正在 Mac OS X Leopard 上的应用程序包中运行 jar 文件。我需要向 jar 中传递一个参数。该参数是调用应用程序包的文件的绝对路径。我在下面有我的简短 bash 脚本。我知道 $0 给出了应用程序包本身的绝对路径。

有谁知道如何在变量中存储我需要的路径（下面的 CALLERPATH）？如果另一个脚本调用它，列出的当前脚本可以正常工作（在 Dennis 的回复中查找调用者脚本），但当我双击“file.xyz”时，它的工作方式不同。

脚本 1

#!/bin/bash
echo $0
echo $_
echo $(dirname $0)
echo $(basename $0)
echo $PWD
echo "$@"
echo $PPID
echo "My PPID echo"
myPPID=$PPID echo $(ps -p $myPPID -o args=)
BASEDIR=`dirname "$0"`
echo "CallerPath Output 1"
callerpath="$(/bin/ps -p $PPID -o args=)"
echo -e "$callerpath\n"
echo "Caller Path Output 2"
callerpath="${callerpath#/bin/bash *}"
echo -e "$callerpath\n"
echo "Final Caller Path"
callerpath="${callerpath%/*}"
echo -e "$callerpath\n"
exec java \
-jar "$BASEDIR/../Resources/Java/myJar.jar" "$callerpath"

输出 1

9/25/09 3:54:42 PM [0x0-0xbb0bb].MyApp[1496] /Applications/appBundle.app/Contents/MacOS/myScript
9/25/09 3:54:42 PM [0x0-0xbb0bb].MyApp[1496] /Applications/appBundle.app/Contents/MacOS/myScript
9/25/09 3:54:42 PM [0x0-0xbb0bb].MyApp[1496] /Applications/appBundle.app/Contents/MacOS 
9/25/09 3:54:42 PM [0x0-0xbb0bb].MyApp[1496] myScript
9/25/09 3:54:42 PM [0x0-0xbb0bb].MyApp[1496] / 
9/25/09 3:54:42 PM [0x0-0xbb0bb].MyApp[1496] -psn_0_766139 
9/25/09 3:54:42 PM [0x0-0xbb0bb].MyApp[1496] 63 
9/25/09 3:54:42 PM [0x0-0xbb0bb].MyApp[1496] My PPID echo 
9/25/09 3:54:42 PM [0x0-0xbb0bb].MyApp[1496] ps: Invalid process id: -o 
9/25/09 3:54:42 PM [0x0-0xbb0bb].MyApp[1496] ps: illegal argument: args= 
9/25/09 3:54:42 PM [0x0-0xbb0bb].MyApp[1496] usage: ps [-AaCcEefhjlMmrSTvwXx] [-O fmt | -o fmt] [-G gid[,gid...]] 
9/25/09 3:54:42 PM [0x0-0xbb0bb].MyApp[1496]           [-g grp[,grp...]] [-u [uid,uid...]] 
9/25/09 3:54:42 PM [0x0-0xbb0bb].MyApp[1496]           [-p pid[,pid...]] [-t tty[,tty...]] [-U user[,user...]] 
9/25/09 3:54:42 PM [0x0-0xbb0bb].MyApp[1496]        ps [-L] 
9/25/09 3:54:42 PM [0x0-0xbb0bb].MyApp[1496] CallerPath Output 1 
9/25/09 3:54:42 PM [0x0-0xbb0bb].MyApp[1496] Caller Path Output 2 
9/25/09 3:54:42 PM [0x0-0xbb0bb].MyApp[1496] Final Caller Path

脚本 2

#!/bin/bash
echo $0
echo $_
echo $(dirname $0)
echo $(basename $0)
echo $PWD
echo "$@"
echo $PPID
echo "My PPID export"
export myPPID=$PPID
echo $(ps -p $myPPID -o args=)
BASEDIR=`dirname "$0"`
echo "CallerPath Output 1"
callerpath="$(/bin/ps -p $PPID -o args=)"
echo -e "$callerpath\n"
echo "Caller Path Output 2"
callerpath="${callerpath#/bin/bash *}"
echo -e "$callerpath\n"
echo "Final Caller Path"
callerpath="${callerpath%/*}"
echo -e "$callerpath\n"
exec java \
-jar "$BASEDIR/../Resources/Java/myJar.jar" "$callerpath"

输出 2

9/25/09 4:02:40 PM [0x0-0xc10c1].MyApp[1561] /Applications/appBundle.app/Contents/MacOS/myScript
9/25/09 4:02:40 PM [0x0-0xc10c1].MyApp[1561] /Applications/appBundle.app/Contents/MacOS/myScript
9/25/09 4:02:40 PM [0x0-0xc10c1].MyApp[1561] /Applications/appBundle.app/Contents/MacOS 
9/25/09 4:02:40 PM [0x0-0xc10c1].MyApp[1561] myScript
9/25/09 4:02:40 PM [0x0-0xc10c1].MyApp[1561] / 
9/25/09 4:02:40 PM [0x0-0xc10c1].MyApp[1561] -psn_0_790721 
9/25/09 4:02:40 PM [0x0-0xc10c1].MyApp[1561] 63 
9/25/09 4:02:40 PM [0x0-0xc10c1].MyApp[1561] My PPID export 
9/25/09 4:02:40 PM [0x0-0xc10c1].MyApp[1561] CallerPath Output 1 
9/25/09 4:02:40 PM [0x0-0xc10c1].MyApp[1561] Caller Path Output 2 
9/25/09 4:02:40 PM [0x0-0xc10c1].MyApp[1561] Final Caller Path 

Answer 1

我有一台 Mac，所以我不能使用 $(readlink -f $0) 技巧。这是我的解决方案，由于我手边没有 Linux 机器，请针对您的系统进行测试：

# Get absolute path of the script
dir=`dirname $0`            # The directory where the script is 
pushd "$dir" > /dev/null    # Go there
CALLERPATH=$PWD             # Record the absolute path
popd > /dev/null            # Return to previous dir

echo $CALLERPATH

它是如何工作的？

策略是 1) 获取目录名，2) cd 到它，3) 记录 $PWD，它总是以绝对路径格式。

Answer 2

这有点杂乱无章，但这里是：

首先，您的标签包括“bash”，但您的 shebang 是针对 /bin/sh。我假设是 Bash。

第一个调用者：

#!/bin/bash
/home/username/dirONE/calltest a b c

下一次调用测试：

#!/bin/bash
# echo some stuff to get our bearings
echo $0
echo $_                                  # should be the same as $0
echo $(dirname $0)
echo $(basename $0)
echo $PWD
echo "$@"
echo $PPID                               # parent process ID
# start making $callerpath, if there are spaces in a dirname or script name, they should be preserved
callerpath="$(ps -p $PPID -o args=)"     # get the command name of the parent (it may have args after it)
callerpath="${callerpath#/bin/bash *}"   # strip /bin/bash from the beginning
callerpath="${callerpath%/*}"            # like dirname, but removes the args, too
echo "$callerpath"

现在运行测试：

$ cd /home/username/dirTHREE
$ /home/username/dirTWO/caller 1 2 3
/home/username/dirONE/calltest
/home/username/dirONE/calltest
/home/username/dirONE
calltest
/home/username/dirTHREE
a b c
32674
/home/username/dirTWO