Symfony2 无法捕获 ResourceNotFoundException

Question

我创建了一个将 uri 转换为带参数的路由名称的服务
我试图捕获 ResourceNotFoundException 不存在的 uris 但得到 500 错误和异常

<?php

namespace OOOO\AdvertisingBundle\Utilities;

use Symfony\Component\Routing\Generator\UrlGeneratorInterface;
use Symfony\Component\Routing\Router;

class RouteConverter
{
    private $router;

    public function __construct(Router $router)
    {
        $this->router = $router;
    }

    public function uriToRoute($uri)
    {
        try {
            $matched = $this->router->match($uri);
        } catch (Exception $e) {

            return null;
        }
        $result['name'] = $matched['_route'];
        unset($matched['_route']);
        unset($matched['_controller']);
        $result['parameters'] = $matched;

        return $result;
    }

    public function generateRoute($name, $parameters)
    {
        try {
            $matched = $this->router->generate($name, $parameters, UrlGeneratorInterface::RELATIVE_PATH);
        } catch (Exception $e) {

            return null;
        }
        return $matched;
    }
}

Answer 1

尝试将Exception 替换为ResourceNotFoundException。并且不要忘记use 声明：

<?php

namespace OOOO\AdvertisingBundle\Utilities;

use Symfony\Component\Routing\Generator\UrlGeneratorInterface;
use Symfony\Component\Routing\Router;
use Symfony\Component\Routing\Exception\ResourceNotFoundException;

class RouteConverter
{
    private $router;

    public function __construct(Router $router)
    {
        $this->router = $router;
    }

    public function uriToRoute($uri)
    {
        try {
            $matched = $this->router->match($uri);
        } catch (ResourceNotFoundException $e) {

            return null;
        }
        $result['name'] = $matched['_route'];
        unset($matched['_route']);
        unset($matched['_controller']);
        $result['parameters'] = $matched;

        return $result;
    }

    public function generateRoute($name, $parameters)
    {
        try {
            $matched = $this->router->generate($name, $parameters, UrlGeneratorInterface::RELATIVE_PATH);
        } catch (ResourceNotFoundException $e) {

            return null;
        }
        return $matched;
    }
}

或者如果你想使用Exception，在 Symfony 中不要忘记名称前的斜线：

<?php

namespace OOOO\AdvertisingBundle\Utilities;

use Symfony\Component\Routing\Generator\UrlGeneratorInterface;
use Symfony\Component\Routing\Router;
use Symfony\Component\Routing\Exception\ResourceNotFoundException;

class RouteConverter
{
    private $router;

    public function __construct(Router $router)
    {
        $this->router = $router;
    }

    public function uriToRoute($uri)
    {
        try {
            $matched = $this->router->match($uri);
        } catch (\Exception $e) {

            return null;
        }
        $result['name'] = $matched['_route'];
        unset($matched['_route']);
        unset($matched['_controller']);
        $result['parameters'] = $matched;

        return $result;
    }

    public function generateRoute($name, $parameters)
    {
        try {
            $matched = $this->router->generate($name, $parameters, UrlGeneratorInterface::RELATIVE_PATH);
        } catch (\Exception $e) {

            return null;
        }
        return $matched;
    }
}