Python 请求异常处理：如何获取更详细（用户友好）的错误消息？答案

【问题标题】：Python requests exception handling: How to get more verbose (user-friendly) error message?Python 请求异常处理：如何获取更详细（用户友好）的错误消息？
【发布时间】：2015-10-31 06:59:12
【问题描述】：

假设我有一些功能：

def get_result(url):
    try:
        return requests.get(url, headers={'User-Agent': random.choice(USER_AGENTS)}).text
    except requests.exceptions.ConnectionError as e:
        message = 'Connection to {0} failed. \n {1}'
        print message.format(url, e)
        sys.exit(0)

案例 #1 “错误的 url 语法” url = 'http://google'

...
 connection to http://google failed. 
 HTTPConnectionPool(host='google', port=80): Max retries exceeded with url: / (Caused by NewConnectionError('<requests.packages.urllib3.connection.HTTPConnection object at 0x7fd417ece350>: Failed to establish a new connection: [Errno -5] No address associated with hostname',))
...

案例#2“不存在的网址” url = 'http://smth_non_existing.com'

...
connection to http://smth_non_existing.com failed. 
 HTTPConnectionPool(host='smth_non_existing.com', port=80): Max retries exceeded with url: / (Caused by NewConnectionError('<requests.packages.urllib3.connection.HTTPConnection object at 0x7fe196d4a3d0>: Failed to establish a new connection: [Errno -2] Name or service not known',))
...

所以我只想打印错误消息的“最后一部分”。第一种情况“没有与主机名关联的地址”，第二种情况“名称或服务未知”

【问题讨论】：

标签： python exception exception-handling python-requests

【解决方案1】：

我找到了您需要的短信 - e.args[0].args[1].args[1]。不清楚，但会打印出来：

Connection to http://google failed. 
 No address associated with hostname

代码：

def get_result(url):
    try:
        return requests.get(url, headers={'User-Agent': random.choice(USER_AGENTS)}).text
    except requests.exceptions.ConnectionError as e:
        message = 'Connection to {0} failed. \n {1}'
        print message.format(url, e.args[0].args[1].args[1])
        sys.exit(0)

【讨论】：