SQLiteConstraintException答案

【问题标题】：SQLiteConstraintExceptionSQLiteConstraintException
【发布时间】：2012-09-29 20:08:36
【问题描述】：

这是我的表格创建命令：

private static final String PINGPONG_CREATE = "create table " + TABLE_PINGPONG + "(" + COLUMN_ID_PINGPONG + " integer primary key autoincrement, " + COLUMN_CNAME +
            " text not null, " + COLUMN_DATE + " text not null, " + " text not null, " + COLUMN_LEAD + " numeric, " + COLUMN_PLACE + " text not null, " 
            + COLUMN_SET_ONE1 + " numeric, " + COLUMN_SET_ONE2 + " numeric, " + COLUMN_SET_TWO1 + " numeric, " + COLUMN_SET_TWO2 + " numeric, " + COLUMN_SET_THREE1
             + " numeric, " + COLUMN_SET_THREE2 + " numeric, " + COLUMN_SET_FOUR1 + " numeric, " + COLUMN_SET_FOUR2 + " numeric, " + COLUMN_SET_FIVE1  + " numeric, " 
            + COLUMN_SET_FIVE2 + " numeric, " + COLUMN_SET_SIX1 + " numeric, " + COLUMN_SET_SIX2 + " numeric, " + COLUMN_SET_SEVEN1 + " numeric, " + COLUMN_SET_SEVEN2
             + " numeric, " + COLUMN_RESULT1 + " numeric, " + COLUMN_RESULT2 + " numeric);";

这是我在数据库中输入“PingPongeEntry”的方法

public void createPingPongEntry(int lead, String challengeName, String date, String place, int set11, int set12, int set21, int set22,
            int set31, int set32, int set41, int set42, int set51, int set52, int set61, int set62, int set71, int set72, int tot1, int tot2){
        ContentValues values = new ContentValues();
        values.put(CustomSQLiteHelper.COLUMN_LEAD, lead);
        values.put(CustomSQLiteHelper.COLUMN_CNAME, challengeName);
        values.put(CustomSQLiteHelper.COLUMN_DATE, date);
        values.put(CustomSQLiteHelper.COLUMN_PLACE, place);
        values.put(CustomSQLiteHelper.COLUMN_SET_ONE1, set11);
        values.put(CustomSQLiteHelper.COLUMN_SET_ONE2, set12);
        values.put(CustomSQLiteHelper.COLUMN_SET_TWO1, set21);
        values.put(CustomSQLiteHelper.COLUMN_SET_TWO2, set22);
        values.put(CustomSQLiteHelper.COLUMN_SET_THREE1, set31);
        values.put(CustomSQLiteHelper.COLUMN_SET_THREE2, set32);
        values.put(CustomSQLiteHelper.COLUMN_SET_FOUR1, set41);
        values.put(CustomSQLiteHelper.COLUMN_SET_FOUR2, set42);
        values.put(CustomSQLiteHelper.COLUMN_SET_FIVE1, set51);
        values.put(CustomSQLiteHelper.COLUMN_SET_FIVE2, set52);
        values.put(CustomSQLiteHelper.COLUMN_SET_SIX1, set61);
        values.put(CustomSQLiteHelper.COLUMN_SET_SIX2, set62);
        values.put(CustomSQLiteHelper.COLUMN_SET_SEVEN1, set71);
        values.put(CustomSQLiteHelper.COLUMN_SET_SEVEN2, set72);
        values.put(CustomSQLiteHelper.COLUMN_RESULT1, tot1);
        values.put(CustomSQLiteHelper.COLUMN_RESULT2, tot2);

        long insertID = database.insert(CustomSQLiteHelper.TABLE_PINGPONG, null, values);

        Cursor cursor = database.query(CustomSQLiteHelper.TABLE_PINGPONG, allColumns3, CustomSQLiteHelper.COLUMN_ID_RUNNING + " = " + insertID, null, null, null, null);
        cursor.moveToFirst();
        cursor.close();
    }

这就是 allColums3-String[]

private String[] allColumns3 = {CustomSQLiteHelper.COLUMN_ID_PINGPONG, CustomSQLiteHelper.COLUMN_CNAME, CustomSQLiteHelper.COLUMN_DATE, CustomSQLiteHelper.COLUMN_PLACE, CustomSQLiteHelper.COLUMN_LEAD,
                                    CustomSQLiteHelper.COLUMN_SET_ONE1,
                                    CustomSQLiteHelper.COLUMN_SET_ONE2, CustomSQLiteHelper.COLUMN_SET_TWO1, CustomSQLiteHelper.COLUMN_SET_TWO2, CustomSQLiteHelper.COLUMN_SET_THREE1, CustomSQLiteHelper.COLUMN_SET_THREE2,
                                    CustomSQLiteHelper.COLUMN_SET_FOUR1, CustomSQLiteHelper.COLUMN_SET_FOUR2, CustomSQLiteHelper.COLUMN_SET_FIVE1, CustomSQLiteHelper.COLUMN_SET_FIVE2, CustomSQLiteHelper.COLUMN_SET_SIX1,
                                    CustomSQLiteHelper.COLUMN_SET_SIX2, CustomSQLiteHelper.COLUMN_SET_SEVEN1, CustomSQLiteHelper.COLUMN_SET_SEVEN2, CustomSQLiteHelper.COLUMN_RESULT1, CustomSQLiteHelper.COLUMN_RESULT2};

现在在long insertID = database.insert(CustomSQLiteHelper.TABLE_PINGPONG, null, values); 行，我收到了 SQLiteConstraintException，但我不知道为什么。它说：

09-29 19:55:13.151: E/Database(1609): Error inserting set51=0 set52=0 set41=3 set61=0 lead=0 set72=0 set71=0 set62=0 date=29-09-2012 result1=4 result2=0 name=pingpong set32=1 set31=3 set42=1 place=hier set22=1 set21=3 set12=1 set11=3

（我也很困惑为什么没有插入值的顺序）

我在这里阅读了一些关于这个主题的问题，但是所有的建议都遵循了：主键是自动递增的，而且此时我试图插入记录，数据库是空的。

我有 2 种方法来插入 FootBallEntrys 和 Games 以此类推，一切正常。那么为什么它不在这里创建一个唯一的 uid 呢？

【问题讨论】：

我认为您在这里创建了一个不能为空的未命名列：+ COLUMN_DATE + " text not null, " + " text not null,。插入时您没有提供该值，因此它会失败。
@zapl 虽然我对表格甚至可以编译感到惊讶，但您应该将其发布为答案。你会得到我的支持。
实际上是我监督的那段代码。如果您将其发布为答案，我当然会接受。

标签： android sqlite exception

【解决方案1】：

如果您得到一个 ConstraintException，则说明您违反了表中的某些约束。您拥有的唯一规则是“主键”，它在后台创建“唯一”约束。确保您没有尝试在“COLUMN_ID_PINGPONG”列中插入已经存在的值。

【讨论】：

还有几个“NOT NULL”约束更可能是原因。