【发布时间】:2019-02-22 13:22:09
【问题描述】:
我是例外的新手,我试图改进我的一个朋友在面试中遇到的问题的解决方案。
我的朋友被要求构建一个程序,该程序将获取 2 个数组并找到一个数字,如果我们将它除以第一个数组的成员,我们将得到第二个数组的匹配余数。
在这种情况下,我可以在没有任何继承类的情况下使用 std::exception 吗?
CPP 文件
#include <iostream>
#include <exception>
#include "FindNumber.h"
Finder::Finder() : m_num(0)
{}
int Finder::FindFirst(int* _divided, int* _leftOver, int _size)
{
int indx = 0;
while(indx < _size)
{
if (!_divided[indx])
{
throw("Can not divide by zero!!");
}
if (m_num % _divided[indx] != _leftOver[indx])
{
++m_num;
FindRest(_divided, _leftOver, _size);
indx = 0;
}
++indx;
}
return m_num;
}
int Finder::FindRest(int* _divided, int* _leftOver, int _size)
{
int indx = 0;
for(;;)
{
if (!_divided[indx])
{
throw("Can not divide by zero!!");
}
if (m_num % _divided[indx] != _leftOver[indx])
{
++m_num;
}
else
{
break;
}
}
return m_num;
}
测试单元
#include <cstdio>
#include <iostream>
#include "FindNumber.h"
#include "mu_test.h"
#define SIZE 5
/****************************** FN_check1 ******************************/
UNIT(FN_check1)
int divided [SIZE] = {0, 4, 5, 6, 7};
int leftOver [SIZE] = {2, 0, 3, 2, 1};
Finder find1;
try
{
ASSERT_THAT(6 != find1.FindFirst(divided, leftOver, SIZE));
ASSERT_THAT(8 == find1.FindFirst(divided, leftOver, SIZE));
}
catch(std::exception& e)
{
std::cout << e.what();
}
END_UNIT
/****************************** FN_check2 ******************************/
UNIT(FN_check2)
int divided [SIZE] = {6, 12, 8, 10, 7};
int leftOver [SIZE] = {0, 0, 4, 2, 5};
Finder find1;
ASSERT_THAT(6 != find1.FindFirst(divided, leftOver, SIZE));
ASSERT_THAT(12 == find1.FindFirst(divided, leftOver, SIZE));
std::cout << find1.FindFirst(divided, leftOver, SIZE) << std::endl;
END_UNIT
TEST_SUITE(FindNumber_test)
TEST(FN_check1)
TEST(FN_check2)
END_SUITE
提前谢谢...
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