在 catch 语句出错后重新启动程序

Question

在使用catch() 函数发现错误后，我正在尝试重新启动我的程序，但我也希望它显示错误，停止程序的其余部分运行，然后重新启动程序。 这只是我用作示例的代码的缩短版本。

using System;

namespace Calculator
{
    internal class Program
    {
        private static void Main(string[] args)
        {
            float input = 0;
            while (input != 5)
            {
                Console.Clear();
                Console.WriteLine("What would you like to do? Type: 1 for Addition. Write 5 to end program.");

                try
                {
                    input = float.Parse(Console.ReadLine());
                }
                catch (FormatException)
                {
                    Console.WriteLine("Please enter a number");
                }
                //Addition
                if (input == 1)
                {
                    Console.WriteLine("Enter First Value: ");
                    string FirstValue = Console.ReadLine();
                    float firstval = 0;
                    try
                    {
                        firstval = float.Parse(FirstValue);
                    }
                    catch (FormatException)
                    {
                        Console.WriteLine("Please enter a number");
                        break;
                    }
                    Console.WriteLine("Enter Second Value: ");
                    string SecondValue = Console.ReadLine();
                    float secval = 0;
                    try
                    {
                        secval = float.Parse(SecondValue);
                    }
                    catch (FormatException)
                    {
                        Console.WriteLine("Please enter a number");
                        break;
                    }
                    float sum = Add(firstval, secval);
                    Console.WriteLine("The sum is: {0}", sum);
                }
            }
        }

        public static float Add(float num1, float num2)
        {
            return num1 + num2;
        }
    }
}

当它说

                    catch (FormatException)
                    {
                        Console.WriteLine("Please enter a number");
                        break;
                    }

break; 使其余代码停止，并显示错误。这很好，但是程序也在那之后结束，我想要的是程序在错误后重复。有什么办法可以发生这种情况，但它允许 1）Console.WriteLine("Please enter a number");，2）程序不运行其余代码（我们被要求提供第二个值的部分），以及 3）程序重新开始。如果这没有意义，请告诉我，因为这很难解释。 :)

Answer 1

这很简单，您不需要“break”关键字，因为“break”终止循环执行以继续执行异常使用“continue”关键字不带引号工作小提琴是here

将“break”替换为“continue”后的代码如下

using System;

namespace Calculator
{
    public class Program
    {
        public static void Main(string[] args)
        {
            float input = 0;
            while (input != 5)
            {
                Console.Clear();
                Console.WriteLine("What would you like to do? Type: 1 for Addition. Write 5 to end program.");

                try
                {
                    input = float.Parse(Console.ReadLine());
                }
                catch (FormatException)
                {
                    Console.WriteLine("Please enter a number");
                }
                //Addition
                if (input == 1)
                {
                    Console.WriteLine("Enter First Value: ");
                    string FirstValue = Console.ReadLine();
                    float firstval = 0;
                    try
                    {
                        firstval = float.Parse(FirstValue);
                    }
                    catch (FormatException)
                    {
                        Console.WriteLine("Please enter a number");
                        continue;
                    }
                    Console.WriteLine("Enter Second Value: ");
                    string SecondValue = Console.ReadLine();
                    float secval = 0;
                    try
                    {
                        secval = float.Parse(SecondValue);
                    }
                    catch (FormatException)
                    {
                        Console.WriteLine("Please enter a number");
                        continue;
                    }
                    float sum = Add(firstval, secval);
                    Console.WriteLine("The sum is: {0}", sum);
                }
            }
        }

        public static float Add(float num1, float num2)
        {
            return num1 + num2;
        }
    }
}