处理递归限制时处理python崩溃答案

【问题标题】：Handling python crash when handling recursion limit处理递归限制时处理python崩溃
【发布时间】：2022-01-04 07:07:34
【问题描述】：

想象一下这段代码：

def a():
    try:
        a()
    except RecursionError:
        a()
a()

似乎 sn-p 会递归地无限运行a 函数。但真正发生的是：

创建递归错误
处理异常，因为您可以处理所有异常
再次做同样的事情结果： python 吓坏了并崩溃（这不可能以我知道的任何方式处理，因为这不会引发错误，它崩溃 python解释器

任何人都可以看到它引发了什么异常：

Fatal Python error: _Py_CheckRecursiveCall: Cannot recover from stack overflow.
Python runtime state: initialized

Current thread 0x00007f2e14fca180 (most recent call first):  File "<stdin>", line 3 in a
  File "<stdin>", line 3 in a
  File "<stdin>", line 3 in a
  File "<stdin>", line 3 in a
  File "<stdin>", line 3 in a
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  File "<stdin>", line 3 in a
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  File "<stdin>", line 3 in a
  File "<stdin>", line 5 in a
  File "<stdin>", line 3 in a
  File "<stdin>", line 3 in a
  File "<stdin>", line 3 in a
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  File "<stdin>", line 3 in a
  File "<stdin>", line 3 in a
  File "<stdin>", line 3 in a
  ...
Aborted (core dumped)

【问题讨论】：

标签： python recursion exception crash crash-dumps

【解决方案1】：

为什么不直接增加系统递归限制？

import sys
sys.setrecursionlimit(1000000000)

【讨论】：

你测试过你的答案吗，因为你的数字太大了，所以 python 引发错误，数字无法转换为 C int + 每当我运行我的代码时它仍然崩溃，只需要等待大约 +1 秒。
对不起，我为了示范而夸大了。但是您可以将限制提高得相当高。我将使用我找到的最大值进行编辑。
顺便说一下，这个解决方案不会阻止 Python 最终崩溃，但它可能有助于延长它需要的时间。你的代码有点……奇怪。
因此，使用新进程隔离可能导致此类崩溃的代码可能会更好？或者有更好的方法来做到这一点？
如果你想让一个函数无限运行（尽可能长时间而不干扰主程序）把你拥有的代码放在一个守护进程中，它应该运行直到你崩溃或者直到你杀死主要过程。我希望这会有所帮助。