【发布时间】:2016-11-28 06:08:24
【问题描述】:
我正在使用 'exec' 调用函数并将参数定义为变量。
$jsonrequest = escapeshellarg(json_encode($request, JSON_NUMERIC_CHECK));
$solveroutput = exec('sudo python /var/www/website.com/services/run.py $jsonrequest');
我已经尝试过这样调用:
$solveroutput = exec("sudo python /var/www/website.com/services/run.py '$jsonrequest'");
和
$solveroutput = exec("sudo python /var/www/website.com/services/run.py $jsonrequest");
也没有'sudo'
当我在服务器 (AWS) 的命令行中直接调用该函数时,我会收到如下结果。上面的$jsonrequest 正是我在命令行中输入的方式。
[lsenna@ip ~]$ sudo python /var/www/website.com/services/run.py '{"max_split":4,"order":681,"max_cost_frac":0.1,"items":[{"productid":8745,"qty":1,"estimatedprice":53.6}],"bids":[{"vendorid":1,"minimum_order":0,"items":[{"productid":8745,"qty":1,"estimatedprice":100}]}]}'
回应:
{"status": "OK", "order": 681, "deliveries": [{"vendorid": 1, "productid": 8745}]}
谢谢!
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