sweetalert：如何将参数传递给回调

Question

我正在使用 javascript 警报库 sweetalert

我的代码是：

function foo(id) {
    swal({
      title: "Are you sure?",
      text: "You will not be able to recover this imaginary file!",
      type: "warning",
      showCancelButton: true,
      confirmButtonColor: "#DD6B55",
      confirmButtonText: "Yes, delete it!",
      closeOnConfirm: false
    },
    function(){
      swal("Deleted!", "Your imaginary file has been deleted.", "success");
    });
}

如何将id 从foo() 函数传递到swal 中的回调函数？

Answer 1

function(id){
  alert(MyId);
  swal("Deleted!", "Your imaginary file has been deleted.", "success");
});

这不起作用，因为在这种情况下 id 是您的确认对话框的选项 isConfirm - 请参阅SweetAlert Documentation。

这会起作用 - 不需要额外的变量：

function foo(id) {
  swal({
    title: "Are you sure?",
    text: "You will not be able to recover this imaginary file!",
    type: "warning",
    showCancelButton: true,
    confirmButtonColor: "#DD6B55",
    confirmButtonText: "Yes, delete it!",
    closeOnConfirm: false
  },
  function(isConfirm){
    alert(isConfirm);
    alert(id);
    swal("Deleted!", "Your imaginary file has been deleted.", "success");
  }); 
} 
foo(10);

这里是 jsfiddle：http://jsfiddle.net/60bLyy2k/

Answer 2

只需将您的参数放在局部变量中，它们可以在内部函数或 clousers 中访问

function foo(id) {
    var MyId = id;
    swal({
      title: "Are you sure?",
      text: "You will not be able to recover this imaginary file!",
      type: "warning",
      showCancelButton: true,
      confirmButtonColor: "#DD6B55",
      confirmButtonText: "Yes, delete it!",
      closeOnConfirm: false
    },
    function(){
        alert(MyId);
      swal("Deleted!", "Your imaginary file has been deleted.", "success");
    });
}

foo(10);

这里是小提琴https://jsfiddle.net/