单击按钮时不会打开提示窗口答案

【问题标题】：Prompt window won't open when clicking on button单击按钮时不会打开提示窗口
【发布时间】：2018-12-16 13:53:01
【问题描述】：

我有一个任务，我必须查看输入的数字是否是 Armstrong 数字，问题是当我单击按钮时，提示窗口不显示，只有在我有其余部分时才会出现写出的函数。单独显示提示窗口时。

function armNum(){
    var num = prompt("Enter a number between 0 and 999!: ");
    var firstNum;
    var secondNum;
    var thirdNum;
    if(num < 100 && num > 0)
    {
        firstNum = num/10;
        secondNum = num%10;
        var StrongNum = (firstNum**3) + (secondNum**3);
        if( num == StrongNum)
        {
            document.getElementById("ispis").innerHTML = "nummber " + num + " is an armstrong number!"
        }
    else

        {
            document.getElementById("ispis").innerHTML = "number" + num + "is not an armstrong number!"
        }
    }
    if(num > 99 && num < 1000)
    {
        firstNum = num/100;
        secondNum = (num/10)%10;
        thirdNum = num % 10;
        var StrongNum = (firstNum**3) + (secondNum**3) = (thirdNum**3);
        if( num == StrongNum)
        {
            document.getElementById("ispis").innerHTML = "nummber " + num + " is an armstrong number!"
        }
        else
        {
            document.getElementById("ispis").innerHTML = "number" + num + "is not an armstrong number!"
        }
    }
}

【问题讨论】：

在 tnis 行 = (firstNum**3) + (secondNum**3) = (thirdNum**3); 中有一个错误，您使用 '=' 而不是关闭 '+'

标签： javascript html css prompt

【解决方案1】：

你在这个字符串上有一个错误（将“=”改为“+”）：

var StrongNum = (firstNum3) + (secondNum3) = (thirdNum**3);
你不调用函数
尝试在你的函数之后添加

armNum();

【讨论】：

【解决方案2】：

tnis 行 = (firstNum**3) + (secondNum**3) = (thirdNum**3); 中有一个错误，您使用了 '=' 而不是 '+' & you

function armNum(){
    var num = prompt("Enter a number between 0 and 999!: ");
    var firstNum;
    var secondNum;
    var thirdNum;
    if(num < 100 && num > 0)
    {
        firstNum = num/10;
        secondNum = num%10;
        var StrongNum = (firstNum**3) + (secondNum**3);
        if( num == StrongNum)
        {
            alert( "nummber " + num + " is an armstrong number!")
        }
    else

        {
            alert( "number" + num + "is not an armstrong number!");        }
    }
    if(num > 99 && num < 1000)
    {
        firstNum = num/100;
        secondNum = (num/10)%10;
        thirdNum = num % 10;
        var StrongNum = (firstNum**3) + (secondNum**3)+(thirdNum**3);
        if( num == StrongNum)
        {
            alert( "nummber " + num + " is an armstrong number!");
        }
        else
        {
            alert("number" + num + "is not an armstrong number!");
        }
    }
}

<body onload=armNum()>
</body>

【讨论】：