使用终端命令在文件中搜索 python 脚本中的特定字符串

Question

我有一个父目录，我想通过该目录并获取每个带有特定字符串的文件，以便在 python 中进行编辑。我一直在终端中使用grep -r 'string' filepath，但我希望能够使用 python 完成所有操作。我希望将所有文件放入一个数组中，然后逐个进行编辑。

有没有办法只通过运行 python 脚本来做到这一点？

Answer 1

将当前文件夹更改为父文件夹

import os    
os.chdir("..")

更改文件夹

import os
os.chdir(dir_of_your_choice)

在当前文件夹中查找带有规则的文件

import glob
import os
current_dir = os.getcwd()
for f in glob.glob('*string*'):
    do_things(f)

Answer 2

import os
#sourceFolder is the folder you're going to be looking inside for backslashes are a special character in python so they're escaped as double backslashes
sourceFolder = "C:\\FolderBeingSearched\\"

myFiles = []

# Find all files in the directory
for file in os.listdir(sourceFolder):
    myFiles.append(file)

#open them for editing
for file in myFiles:
    try:
        open(sourceFolder + file,'r')
    except:
        continue 

    #run whatever code you need to do on each open file here
    print("opened %s" % file)

编辑：如果你想分隔所有包含字符串的文件（这只是打印当前末尾的列表）：

import os
#sourceFolder is the folder you're going to be looking inside for backslashes are a special character in python so they're escaped as double backslashes
sourceFolder = "C:\\FolderBeingSearched\\"

myFiles = []
filesContainString = []
stringsImLookingFor = ['first','second']
# Find all files in the directory
for file in os.listdir(sourceFolder):
    myFiles.append(file)

#open them for editing
for file in myFiles:

    looking = sourceFolder + file

    try:
        open(looking,'r')        
    except:
        continue 

    print("opened %s" % file)

    found = 0
    with open(looking,encoding="latin1") as in_file:
        for line in in_file:
            for x in stringsImLookingFor:
                if line.find(x) != -1:
                    #do whatever you need to do to the file or add it to a list like I am
                    filesContainString.append(file)
                    found = 1
                    break
            if found:
                break

print(filesContainString)