从列表中创建文件夹和子文件夹，每个文件夹中有 1 个文件

Question

我有一个这样的数据框：

mgr1       mgr2      mgr3
abc        def       fed
asd        dij       
sdf

df 确实包含空值

我正在尝试创建一个目录，其中唯一的 mgr3 值是顶级文件夹的名称，mgr2 唯一值是子文件夹，mgr1 唯一值是第二个子文件夹中的文件夹等。然后在每个文件夹中添加一个 txt 文件。

我将每列转换为具有唯一字符串的变量，然后尝试执行一些 for 循环以基于这些字符串创建文件夹，但我没有成功。

#someting like this
mgr1 = list(set(df.mgr1))
mgr1 = [x for x in mgr1 if str(x) != 'nan']
mgr1 = ''.join(mgr1)
# print(mgr1)

for i in mgr1:
    os.system ("mkdir "+i)
    for j in range (1):
            os.system ("touch "+str(i)+"/"+str(j)+".txt")

有什么想法吗？

尝试 1：

import os
import sys
import pandas as pd
import itertools

df = pd.read_csv('sas-user-mappings-to-ceo.csv')

eight = df.loc[~df['mgr8'].isnull(), 'mgr8'].tolist()
seven = df.loc[~df['mgr7'].isnull(), 'mgr7'].tolist()
six = df.loc[~df['mgr6'].isnull(), 'mgr6'].tolist()
five = df.loc[~df['mgr5'].isnull(), 'mgr5'].tolist()
four = df.loc[~df['mgr4'].isnull(), 'mgr4'].tolist()
three = df.loc[~df['mgr3'].isnull(), 'mgr3'].tolist()
two = df.loc[~df['mgr2'].isnull(), 'mgr2'].tolist()
one = df.loc[~df['mgr1'].isnull(), 'mgr1'].tolist()
user_name = df.loc[~df['user_name'].isnull(), 'user_name'].tolist()
# third = df.loc[~df['user_lid'].isnull(), 'user_lid'].tolist()

paths = [list(x) for x in itertools.product(eight, seven, six, five, four, three, two, one, user_name)]

for pathToWrite in paths:
    pathToWrite = "\Users\max\Downloads\users_visual"
    toCreate = os.path.join("C:", pathToWrite)

    os.mkdir(toCreate)

error: SyntaxError: (unicode error) 'unicodeescape' codec can't decode bytes in position 0-1: truncated \UXXXXXXXX escape

Answer 1

import itertools

base = df.loc[~df['mgr3'].isnull(), 'mgr3'].tolist()
sec = df.loc[~df['mgr2'].isnull(), 'mgr2'].tolist()
third = df.loc[~df['mgr1'].isnull(), 'mgr1'].tolist()

paths = [list(x) for x in itertools.product(base, sec, third)]

for pathToWrite in paths:
    #change the path to where ever you need to
    toCreate = os.path.join("C:", *pathToWrite)

    os.mkdir(toCreate)

在单独的列表中获取所有路径。由于我不知道您的列是否已订购，因此我只是在单独的行上进行了操作。使用 itertools 创建所有路径，然后遍历路径列表并制作它。