如何在 ksh 脚本报告中对齐十进制值答案

【问题标题】：how to align the decimal values in a ksh script report如何在 ksh 脚本报告中对齐十进制值
【发布时间】：2015-02-24 17:15:26
【问题描述】：

我正在尝试对齐 awk 中的值。但仍然面临一些对齐问题。请您帮忙。

我正在低于格式。，

                Code 0011               0.00
                Code 0012               0.00
                Code   17               1,234.23
                Code   37               123,456.12
                Code   41               2,345.12
           Total Amount                 8.41
          0011 Record Count              0
         0012 Record Count              0
           17 Record Count              2
           37 Record Count              1
           41 Record Count              2
        Total Record Count              1

但我期待如下。，所有小数都需要正确对齐..

                Code 0011                    0.00
                Code 0012                    0.00
                Code   17                1,234.23
                Code   37              123,456.12
                Code   41                2,345.12
           Total Amount                      8.41
          0011 Record Count             0
         0012 Record Count              0
           17 Record Count              2
           37 Record Count              1
           41 Record Count              2
        Total Record Count              1

记录数也需要与上一行匹配，

            Code   37                    123,456.12
            Code   41                      2,345.12
           Total Amount                        0.00
         0319 Record Count                        0
         0329 Record Count                       11                    
         0339 Record Count                      321

这是我尝试过的代码。，

awk -F, -v outfile="$outfile" -v ts="$ts"  -v tc="$tc" -v sq="'" '
     {
            printf("%14s Code %s%15s%" sq ".2f\n"," ",$1," ",$2) >> outfile
            r[NR] = $1
            c[NR] = $3
    }
      END {printf("%14s Total Amount                 %" sq ".2f\n "," ",ts) >> outfile
              for(i = 1; i <= NR; i++) printf("%12s %s Record Count %11s  %s\n"," ",r[i]," ",c[i]) >> outfile
     }' FS=, OFS=, trancodestotalsumt.txt

【问题讨论】：

标签： shell awk sh

【解决方案1】：

您需要知道我trancodestotalsumt.txt 可以拥有的数字的最大长度，或者处理文件两次以在第一遍中计算它。假设你知道最大宽度，替换

printf("%14s Code %s%15s%" sq ".2f\n"," ",$1," ",$2) >> outfile

与

#                              vv--- here
printf("%14s Code %s%15s%" sq "10.2f\n"," ",$1," ",$2) >> outfile

将标记的宽度扩展到 n 个字符（在本例中为 10 个）。

要记住第一遍的长度，记住我没有测试数据，请使用

awk -F, -v outfile="$outfile" -v ts="$ts"  -v tc="$tc" -v sq="'" '
     NR == FNR {
       width = length(sprintf("%" sq ".2f", $2));
       if(width > maxwidth) maxwidth = width;
       next
     }
     {
        printf("%14s Code %s%15s%" sq maxwidth ".2f\n"," ",$1," ",$2) >> outfile
        r[NR] = $1
        c[NR] = $3
     }
     END {
         printf("%14s Total Amount                 %" sq ".2f\n "," ",ts) >> outfile
         for(i = 1; i <= NR; i++) printf("%12s %s Record Count %11s  %s\n"," ",r[i]," ",c[i]) >> outfile
     }' FS=, OFS=, trancodestotalsumt.txt trancodestotalsumt.txt

开头插入的块，

     NR == FNR {
       width = length(sprintf("%" sq ".2f", $2));
       if(width > maxwidth) maxwidth = width;
       next
     }

在文件的第一次传递期间执行，当FNR == NR 时，其余在第二次传递。请注意，trancodestotalsumt.txt 在最后被赋予 awk 两次以完成这项工作。

【讨论】：