awk脚本调整格式

Question

我正在尝试使用以下 awk 脚本从名为 file.txt 的文件中计算 每 1000 个 记录并将这些记录括在括号中

file.txt 的内容

12345

23456

43567

awk '{ printf $0 " " } NR%1000 == 0 { print "" }' file.txt | sed 's/.*/(&)/'

输出

(12345 23456 43567)

我需要将此输出与 mysql 批量删除语句 相关联，例如以下

Delete from ReportingDetail where ReportingDetailID IN (12345,23456,43567); 

1. 我无法添加“从 ReportingDetail 中删除 ReportingDetailID IN" 到每一行的合并。
2. 我无法在记录之间添加“，”。

非常感谢您的帮助！

Answer 1

您只能使用 sed 来做到这一点：

sed -e 's/ /,/g' -e 's/^/Delete from ReportingDetail where ReportingDetailID IN (/' -e 's/$/)/' file.txt

例如：

$ echo "1 2 3"|sed -e 's/ /,/g' -e 's/^/Delete from ReportingDetail where ReportingDetailID IN (/' -e 's/$/)/'
Delete from ReportingDetail where ReportingDetailID IN (1,2,3)

编辑 - 对于您的更新（即当您在不同的行上有数字时），只需添加您已经拥有的内容：

awk '{ printf $0 " " } NR%1000 == 0 { print "" }' file.txt | sed -e 's/ /,/g' -e 's/^/Delete from ReportingDetail where ReportingDetailID IN (/' -e 's/,$/)/'

例如：

$ echo -e "1\n2\n3"|awk '{ printf $0 " " } NR%1000 == 0 { print "" }'|sed -e 's/ /,/g' -e 's/^/Delete from ReportingDetail where ReportingDetailID IN (/' -e 's/,$/)/'
Delete from ReportingDetail where ReportingDetailID IN (1,2,3)

你也可以像这样不使用 awk：

$ echo -e "1\n2\n3\n4"|tr "\n" " "|sed -e 's/ /,/g' -e 's/^/Delete from ReportingDetail where ReportingDetailID IN (/' -e 's/,$/)/'
Delete from ReportingDetail where ReportingDetailID IN (1,2,3,4)

请注意，我使用的 echo 仅用于测试，即这是它产生的：

$ echo -e "1\n2\n3\n4"
1
2
3
4