在模式匹配处打印连续的 3 行

Question

我有一个巨大的文件，我需要对模式匹配“vm”的 3 行进行排序和合并，并将它们合并到单行中，如下所示

kfg-ap4 是服务器名称，我们只能拥有它一次，在排序时会很好.. 我用 getline 尝试了 awk，但不知何故我想不适合它..

awk '/vm/ {printf $0 " ";getline;打印 $0}' mem_overc

**[kfg-ap4] out: vm.overcommit_memory = 0 [kfg-ap4] out: vm.overcommit_ratio = 50 [kfg-ap4] out: vm.nr_overcommit_hugepages = 0**


[kfg-ap4] Executing task 'moc'
[kfg-ap4] sudo: /sbin/sysctl -A | grep overcommit
[kfg-ap4] out:
[kfg-ap4] out: We trust you have received the usual lecture from the local System
[kfg-ap4] out: Administrator. It usually boils down to these three things:
[kfg-ap4] out:
[kfg-ap4] out:     #1) Respect the privacy of others.
[kfg-ap4] out:     #2) Think before you type.
[kfg-ap4] out:     #3) With great power comes great responsibility.
[kfg-ap4] out:
[kfg-ap4] out: sudo password:

[kfg-ap4] out: vm.overcommit_memory = 0
[kfg-ap4] out: vm.overcommit_ratio = 50
[kfg-ap4] out: vm.nr_overcommit_hugepages = 0

[kfg-ap4] out:

================================================ ========================

实际数据如下，除服务器名称外其余数据相同

[kfg-ap3] Executing task 'moc'
[kfg-ap3] sudo: /sbin/sysctl -A | grep overcommit
[kfg-ap3] out:
[kfg-ap3] out: We trust you have received the usual lecture from the local System
[kfg-ap3] out: Administrator. It usually boils down to these three things:
[kfg-ap3] out:
[kfg-ap3] out:     #1) Respect the privacy of others.
[kfg-ap3] out:     #2) Think before you type.
[kfg-ap3] out:     #3) With great power comes great responsibility.
[kfg-ap3] out:
[kfg-ap3] out: sudo password:
[kfg-ap3] out: vm.overcommit_memory = 0
[kfg-ap3] out: vm.overcommit_ratio = 50
[kfg-ap3] out: vm.nr_overcommit_hugepages = 0
[kfg-ap3] out:

[kfg-ap4] Executing task 'moc'
[kfg-ap4] sudo: /sbin/sysctl -A | grep overcommit
[kfg-ap4] out:
[kfg-ap4] out: We trust you have received the usual lecture from the local System
[kfg-ap4] out: Administrator. It usually boils down to these three things:
[kfg-ap4] out:
[kfg-ap4] out:     #1) Respect the privacy of others.
[kfg-ap4] out:     #2) Think before you type.
[kfg-ap4] out:     #3) With great power comes great responsibility.
[kfg-ap4] out:
[kfg-ap4] out: sudo password:
[kfg-ap4] out: vm.overcommit_memory = 0
[kfg-ap4] out: vm.overcommit_ratio = 50
[kfg-ap4] out: vm.nr_overcommit_hugepages = 0
[kfg-ap4] out:

Answer 1

你快到了：只需在变量中累积并最终打印：

awk 'BEGIN{s="";} /vm/ {s = s $0 " "} END {print s}' log.txt

您还可以使用您的确切构造并转换换行符：

awk '/vm/ {printf $0 " ";getline; print $0}' log.txt | tr "\n" " "

Answer 2

$ awk '/vm/ {printf "%s%s", $0, (++i%3?OFS:ORS)}' log.txt
[kfg-ap4] out: vm.overcommit_memory = 0 [kfg-ap4] out: vm.overcommit_ratio = 50 [kfg-ap4] out: vm.nr_overcommit_hugepages = 0
[kfg-ap4] out: vm.overcommit_memory = 0 [kfg-ap4] out: vm.overcommit_ratio = 50 [kfg-ap4] out: vm.nr_overcommit_hugepages = 0

步行：

/vm/ {                                 # if vm on the record
    printf "%s%s", $0, (++i%3?OFS:ORS) # print record and OFS
}                                      # every 3rd time print ORS

因为实际上一组中有超过 3 行，所以使用这个：

$ awk '/vm/ {buf=buf OFS $0; next} buf!="" {print buf; buf=""}'

它会缓冲记录并在遇到与/vm/ 不匹配的记录后将其打印出来。如果您的文件中有连续的组，则可能会出现问题。您最终可能会得到比预期更长的行。

$ cat > process.awk
/vm/ {              # if vm string in the record
    buf=buf OFS $0  # append the record $0 to the buffer variable buf
    next            # skip the rest of script for this record, ie.
}                   # only records without vm match get past this point
buf!="" {           # if the buffer is not empty
    print buf       # print it out
    buf=""          # empty the buffer
}
$ awk -f process.awk log.txt

Answer 3

仅使用sed 的另一个答案

/vm/{
H
x
s/\n/ /g
s/ \[kfg-ap.\] out: / /
x
blab
}
x
p
:lab

像这样调用（将上面的文件保存为filter.sed）：

sed -n -f filter.sed text.txt 

如果vm 匹配，则存储在保持缓冲区中。然后交换整个缓冲区以删除行中的换行符和无用的 kfg 前缀，再次交换。

如果不匹配，再次交换缓冲区并打印。

相当简单且效果很好（极端情况：如果日志以 vm 行结尾，则可以省略它们）