无法绑定多部分标识符 - SQL Server 2014

Question

我正在尝试解决以下查询中的错误

是的，我检查了许多相同的问题，但仍然无法找出解决方案

错误：

无法绑定多部分标识符“Table_2.id”。

当我删除内部连接时，查询运行良好

我必须在不将其转换为显式联接的情况下解决此问题，因为我有很多动态过滤，它们会将 and x=y 子句添加到查询的末尾

谢谢

SELECT TOP 10 username, 
              NAME, 
              table_1.authoritylevel, 
              totalcount, 
              avglevel, 
              table_2.pokemonid, 
              pokemonlevel, 
              table_2.id, 
              pokemonexp, 
              battlecount, 
              battlevictorycount, 
              table_1.userid 
FROM   table_1, 
       table_2, 
       table_3, 
       table_4 
       LEFT OUTER JOIN (SELECT Count(table_5.offereruserid) AS OfferCount, 
                               table_5.offereduserspokemonsid 
                        FROM   table_5 
                        GROUP  BY offereduserspokemonsid) innerQuestion 
                    ON innerQuestion.offereduserspokemonsid = table_2.id 
WHERE  table_3.pokemonid = table_2.pokemonid 
       AND pokemonplace = 'trade' 
       AND table_4.pokemonid = table_2.pokemonid 
       AND table_2.userid = table_1.userid 
       AND table_2.userid != 1 

Answer 1

如果您热衷于保留隐式连接，则可以使用 WITH 将查询拆分为多个结果集。根据this article，你不能再做“隐式外连接”。试试这个：

WITH OfferCounts as
(
    SELECT Count(table_5.offereruserid) AS OfferCount,  table_5.offereduserspokemonsid 
    FROM table_5 
    GROUP  BY offereduserspokemonsid
),
EverythingElse AS
(
    SELECT TOP 10 username, 
                  NAME, 
                  table_1.authoritylevel, 
                  totalcount, 
                  avglevel, 
                  table_2.pokemonid, 
                  pokemonlevel, 
                  table_2.id, 
                  pokemonexp, 
                  battlecount, 
                  battlevictorycount, 
                  table_1.userid 
    FROM   table_1, 
           table_2, 
           table_3, 
           table_4,
    WHERE  table_3.pokemonid = table_2.pokemonid 
           AND pokemonplace = 'trade' 
           AND table_4.pokemonid = table_2.pokemonid 
           AND table_2.userid = table_1.userid 
           AND table_2.userid != 1 

)
Select * 
From EverythingElse t1
    left join OfferCounts t2 on t1.offereduserspokemonsid = t2.id

Answer 2

具体问题来自于先使用隐式连接，然后再使用显式连接。较少的代码行不是使用隐式连接的好理由，特别是因为它已被弃用。

另一个考虑因素是使用表别名，并为每一列加上相应的表别名，即使列在这些表之间是唯一的，以提高可读性和更易于维护的代码。

您还缺少聚合函数所需的GROUP BY。总而言之，固定代码是：

SELECT TOP 10 username, 
              NAME, 
              T1.authoritylevel, 
              totalcount, 
              avglevel, 
              T2.id, 
              T2.pokemonid, 
              pokemonlevel, 
              pokemonexp, 
              battlecount, 
              battlevictorycount, 
              T1.userid, 
              Count(T5.offereruserid) AS OfferCount 
FROM   Table_1 T1
INNER JOIN Table_2 T2
    ON T1.userid = T2.userid
INNER JOIN Table_3 T3
    ON T2.pokemonid = T3.pokemonid
INNER JOIN Table_4 T4
    ON T2.pokemonid = T4.pokemonid
INNER JOIN Table_5 T5
       ON T5.offereduserspokemonsid = T2.id 
WHERE  pokemonplace = 'trade' 
       AND T2.userid != 1 
GROUP BY  username, 
          NAME, 
          T1.authoritylevel, 
          totalcount, 
          avglevel, 
          T2.id, 
          T2.pokemonid, 
          pokemonlevel, 
          pokemonexp, 
          battlecount, 
          battlevictorycount, 
          T1.userid;

但是，正如我所说，我建议您为这些列添加相应的前缀。