调用arrange后合并两个数据帧时出错答案

【问题标题】：Error when merging two data frames after calling arrange调用arrange后合并两个数据帧时出错
【发布时间】：2014-05-10 00:39:28
【问题描述】：

我有两个名为“a1”和“a2”的数据帧，它们是由 read.csv 引入的，每个数据帧都有一个名为“time”的列，我使用 strptime 将类设置为 POSIXlt。

在尝试合并数据帧之前，我调用了 arrange(a1, time) 和 arrange(a2, time) 以获得从最旧到最新的顺序。然后我尝试调用ahu1 <- merge(a1, a2) 开始将它们放在一起并得到以下错误：

Error in sort.list(bx[m$xi]) : 'x' must be atomic for 'sort.list'
Have you called 'sort' on a list?

调用str(a1) 和str(a2) 验证两者实际上都是数据框，并且它们具有相同的观察总数。我错过了什么或做错了什么？

structure(list(time = structure(list(sec = c(0, 0, 0, 0, 0, 0), min = c(0L, 15L, 30L, 45L, 0L, 15L), hour = c(10L, 10L, 10L, 10L, 11L, 11L), mday = c(24L, 24L, 24L, 24L, 24L, 24L), mon = c(1L, 
1L, 1L, 1L, 1L, 1L), year = c(114L, 114L, 114L, 114L, 114L, 114L), wday = c(1L, 1L, 1L, 1L, 1L, 1L), yday = c(54L, 54L, 54L, 54L, 54L, 54L), isdst = c(0L, 0L, 0L, 0L, 0L, 0L), zone = c("MST", 
"MST", "MST", "MST", "MST", "MST"), gmtoff = c(NA_integer_, NA_integer_, NA_integer_, NA_integer_, NA_integer_, NA_integer_)), .Names = c("sec", "min", "hour", "mday", "mon", "year", "wday", "yday", "isdst", "zone", "gmtoff"), class = c("POSIXlt", "POSIXt")), status.sf = c("TRUE", "TRUE", "TRUE", "TRUE", "TRUE", "TRUE"), status.rf = c("TRUE", "TRUE", "TRUE", "TRUE", "TRUE", "TRUE"), cfm.oa = c(1397.6, 343, 1265, 1500, 744.5, 1261.6), cfm.ra = c("2364.8", "3067.4", "2073.9", "2727.4", "2561.2", "2032.4"), temp.ra = c(68.6, 67.6, 69.1, 69.7, 67.9, 69), temp.ma = c(65.6, 65.8, 66.8, 67.9, 66.5, 68.2), temp.sa = c(51.1, 66.4, 68.6, 51.2, 67.3, 68), ductstatic = c(0.25, 0.25, 0.25, 0.47, 0.27, 0.25), fault.hum = c("FALSE", "FALSE", "FALSE", "FALSE", "FALSE", "FALSE"), fltpress = c(0.15, 0.12, 0.12, 0.22, 0.13, 0.13), fault.smoke = c("FALSE", "FALSE", "FALSE", "FALSE", "FALSE", "FALSE")), .Names = c("time", "status.sf", "status.rf", "cfm.oa", "cfm.ra", "temp.ra", "temp.ma", "temp.sa", 
"ductstatic", "fault.hum", "fltpress", "fault.smoke"), row.names = c(NA, 6L), class = "data.frame")



structure(list(time = structure(list(sec = c(0, 0, 0, 0, 0, 0), min = c(0L, 15L, 30L, 45L, 0L, 15L), hour = c(10L, 10L, 10L, 10L, 11L, 11L), mday = c(24L, 24L, 24L, 24L, 24L, 24L), mon = c(1L, 1L, 1L, 1L, 1L, 1L), year = c(114L, 114L, 114L, 114L, 114L, 114L), wday = c(1L, 1L, 1L, 1L, 1L, 1L), yday = c(54L, 54L, 54L, 54L, 54L, 54L), isdst = c(0L, 0L, 0L, 0L, 0L, 0L), zone = c("MST", "MST", "MST", "MST", "MST", "MST"), gmtoff = c(NA_integer_, NA_integer_, NA_integer_, NA_integer_, NA_integer_, NA_integer_)), .Names = c("sec", "min", "hour", "mday", "mon", "year", "wday", "yday", "isdst", "zone", "gmtoff"), class = c("POSIXlt", "POSIXt")), occpt = c("TRUE", "TRUE", "TRUE", "TRUE", "TRUE", "TRUE"), max.dmprpos = c(77, 63, 71, 93, 63, 71), mode.ecm = c("TRUE", "TRUE", "TRUE", "TRUE", "TRUE", "TRUE"), mode.dehum = c("TRUE", "FALSE", "FALSE", "FALSE", "FALSE", "FALSE"), spt.sa = c("53", "66", "66", "66", "66", "66"
), spt.ductstatic = c("0.27", "0.25", "0.25", "0.57", "0.25", "0.25"), mode.co2 = c("FALSE", "FALSE", "FALSE", "FALSE", "FALSE", "FALSE"), mode.hum = c("FALSE", "FALSE", "FALSE", "FALSE", "FALSE", "FALSE"), max.runreqt = c("0", "0", "0", "0", "0", "0"), max.vavco2 = c("427", "429", "427", "414", "417", "406"), max.vavrhv = c("59", "56.4", "54.9", "56.1", "53.3", "50.1"), cfm.vavtot = c("2711", "2383.6", 
"2395.8", "3702.9", "2449.8", "2388.4"), spt.cfm.ra = c("2461", "2133", "2144.3", "3433.7", "2198.8", "2139.3")), .Names = c("time", "occpt", "max.dmprpos", "mode.ecm", "mode.dehum", "spt.sa", "spt.ductstatic", "mode.co2", "mode.hum", "max.runreqt", "max.vavco2", "max.vavrhv", "cfm.vavtot", "spt.cfm.ra"), row.names = c(NA, 6L), class = "data.frame")

【问题讨论】：

您能否编辑dput(head(a1)) 和dput(head(a2)) 的结果，这会使您的问题reproducible？（另外，请不要担心我删掉了你帖子的第一句话；这只是 Stack Exchange 的政策，以避免出现这样的句子）。以多行显示您的代码也是一个好主意（您可以将其缩进四个字符，就像我对您的错误消息所做的那样）而不是将其与文本混合。
arrange 来自哪里？似乎不在基地。
来自 plyr（应在上面的问题中添加 library(plyr)）。然而，这个问题并没有明确说明他是做了a1 <- arrange(a1, time)（这会起作用）还是只是arrange(a1, time)（这不会做任何事情）
?arrange : 在指定的包和库中没有关于“arrange”的文档：你可以试试“??arrange”
?plyr::arrange 会给你帮助文件

标签： r merge dataframe

【解决方案1】：

无论如何，目前这两个数据对象的拖车数量完全相同，日期时间也相同。所以只使用 cbind() 将是一个简单的步骤。 time 列不匹配。

 cbind(a1, a2[-1])

                 time status.sf status.rf cfm.oa cfm.ra temp.ra temp.ma temp.sa
1 2014-02-24 10:00:00      TRUE      TRUE 1397.6 2364.8    68.6    65.6    51.1
2 2014-02-24 10:15:00      TRUE      TRUE  343.0 3067.4    67.6    65.8    66.4
3 2014-02-24 10:30:00      TRUE      TRUE 1265.0 2073.9    69.1    66.8    68.6
4 2014-02-24 10:45:00      TRUE      TRUE 1500.0 2727.4    69.7    67.9    51.2
5 2014-02-24 11:00:00      TRUE      TRUE  744.5 2561.2    67.9    66.5    67.3
6 2014-02-24 11:15:00      TRUE      TRUE 1261.6 2032.4    69.0    68.2    68.0
  ductstatic fault.hum fltpress fault.smoke occpt max.dmprpos mode.ecm
1       0.25     FALSE     0.15       FALSE  TRUE          77     TRUE
2       0.25     FALSE     0.12       FALSE  TRUE          63     TRUE
3       0.25     FALSE     0.12       FALSE  TRUE          71     TRUE
4       0.47     FALSE     0.22       FALSE  TRUE          93     TRUE
5       0.27     FALSE     0.13       FALSE  TRUE          63     TRUE
6       0.25     FALSE     0.13       FALSE  TRUE          71     TRUE
  mode.dehum spt.sa spt.ductstatic mode.co2 mode.hum max.runreqt max.vavco2
1       TRUE     53           0.27    FALSE    FALSE           0        427
2      FALSE     66           0.25    FALSE    FALSE           0        429
3      FALSE     66           0.25    FALSE    FALSE           0        427
4      FALSE     66           0.57    FALSE    FALSE           0        414
5      FALSE     66           0.25    FALSE    FALSE           0        417
6      FALSE     66           0.25    FALSE    FALSE           0        406
  max.vavrhv cfm.vavtot spt.cfm.ra
1         59       2711       2461
2       56.4     2383.6       2133
3       54.9     2395.8     2144.3
4       56.1     3702.9     3433.7
5       53.3     2449.8     2198.8
6       50.1     2388.4     2139.3

【讨论】：