使用逗号分隔符将字典中的每 100 个字符串键添加到字符串数组中

Question

所以我有一个包含 450 个或有时 1313 个字符串键的字典，我想将所有键添加到字符串数组中，因此每个字符串必须包含 1 到 100 个键，这取决于字典的大小。 例如，如果有 450 个键：

let array = ["first 100 keys here comma separated","second 100 keys here comma separated","third 100 keys here comma separated","fourth 100 keys here comma separated","and last 50 keys comma separated"]

Answer 1

您只需对数组元素进行分组并使用 map 使用 joined(separator: ", ") 加入您的键：

extension Array {
    func group(of n: IndexDistance) -> Array<Array> {
        return stride(from: 0, to: count, by: n)
        .map { Array(self[$0..<Swift.min($0+n, count)]) }
    }
}

---

测试：

let dic = ["f":1,"a":1,"b":1,"c":1,"d":1,"e":1, "g": 1]
let arr = Array(dic.keys).group(of: 2).map{
    $0.joined(separator: ", ")
}
arr  //["b, a", "c, f", "e, g", "d"]