用 1 dict 代替 2 dict 得到结果

Question

我只想用 1 个 dict（结果）代替 2 个 dict（男性，女性），然后一切都正确地放入该 dict 中，然后我只打印它们。

谁能帮帮我，好吗？

import csv

males = {}
females = {}

with open('1000 Records.csv') as csv_file:
    csv_reader = csv.reader(csv_file)

    for row in csv_reader:
        year_of_joining = int(row[17])
        quarter_of_joining = row[15]
        gender = row[5]
        result = males if gender == 'M' else females

        if year_of_joining not in result:
            result[year_of_joining] = {f'Q{i + 1}': 0 for i in range(4)}

        result[year_of_joining][quarter_of_joining] += 1


years = list(males.keys()) + list(females.keys())
years = sorted(list(set(years)))

for year in years:
    count = [males.get(year, 0), females.get(year, 0)]
    print("People who join in H1 and H2: %s: %s" % (year, count))

Answer 1

如果这是您想要实现的目标，请告诉我，因为这个问题对我来说并不完全清楚。

import csv


results={'males':{},'females':{}}

with open('1000 Records.csv') as csv_file:
    csv_reader = csv.reader(csv_file)

    for row in csv_reader:
        year_of_joining = int(row[17])
        quarter_of_joining = row[15]
        gender = 'males' if row[5] == 'M' else 'females'
        

        if year_of_joining not in results[gender]:
            results[gender][year_of_joining] = {f'Q{i + 1}': 0 for i in range(4)}
            
        results[gender][year_of_joining][quarter_of_joining] += 1


years = list(results['males'].keys()) + list(results['females'].keys())
years = sorted(list(set(years)))

for year in years:
    count = [results['males'].get(year, 0), results['females'].get(year, 0)]
    print("People who join in H1 and H2: %s: %s" % (year, count))