将具有日期值的字典转换为具有日期值的数据框作为每个月的计数

Question

我一直在努力将下面的 x 字典转换为下面的表格/字典。

 x = {'John': 0,
 'Dan': 0,
 'Tim': 0,
 'Andrew': ['2022-04-10','2022-04-11','2022-06-16','2022-06-17','2022-06-18','2022-08-19','2022-08-20','2022-11-24','2022-12-12'],
 'Jack': ['2021-12-31','2022-01-01','2022-01-02','2022-03-26','2022-03-27','2022-03-28','2022-05-29','2022-06-01','2022-06-10','2022-06-12','2022-08-13']}

我想将名称（键）放入第 0 列， 我想只显示每个年月列的计数

的日期

结果：

df = pd.DataFrame(data = {'Name':['John', 'Dan', 'Tim', 'Andrew', 'Jack'],
    '2021-12':[0,0,0,0,1],
   '2022-01' :[0,0,0,0,2],
   '2022-02' :[0,0,0,0,0],
   '2022-03' :[0,0,0,0,3],
   '2022-04' :[0,0,0,1,0],
    '2022-05' :[0,0,0,0,1],
    '2022-06' :[0,0,0,3,3],
    '2022-07' :[0,0,0,0,0],
    '2022-08' :[0,0,0,2,1],
    '2022-09' :[0,0,0,0,0],
    '2022-10' :[0,0,0,0,0],
    '2022-11' :[0,0,0,1,0],
    '2022-12' :[0,0,0,1,0]})

这是最终的 df 结果（值表示每个月的计数）：

Answer 1

IIUC，你可以试试这样的：

x = {'John': 0,
 'Dan': 0,
 'Tim': 0,
 'Andrew': ['2022-04-10','2022-04-11','2022-06-16','2022-06-17','2022-06-18','2022-08-19','2022-08-20','2022-11-24','2022-12-12'],
 'Jack': ['2021-12-31','2022-01-01','2022-01-02','2022-03-26','2022-03-27','2022-03-28','2022-05-29','2022-06-01','2022-06-10','2022-06-12','2022-08-13']}

dfe = pd.DataFrame.from_dict(x, 'index').explode(0).set_axis(['dates'], axis=1).rename_axis('name').reset_index()

dfe['dates'] = pd.to_datetime(dfe['dates'], format='%Y-%m-%d')

df_out = dfe.groupby(['name',pd.Grouper(key='dates', freq='M')]).size().unstack(fill_value=0)
df_out = df_out.drop('1970-01-31', axis=1)
df_out = df_out.reindex(pd.date_range(df_out.columns.min(), df_out.columns.max(), freq='M'), axis=1, fill_value=0)
df_out.columns = df_out.columns.strftime('%Y-%m')
print(df_out)

输出：

        2021-12  2022-01  2022-02  2022-03  2022-04  2022-05  2022-06  2022-07  2022-08  2022-09  2022-10  2022-11  2022-12
name                                                                                                                       
Andrew        0        0        0        0        2        0        3        0        2        0        0        1        1
Dan           0        0        0        0        0        0        0        0        0        0        0        0        0
Jack          1        2        0        3        0        1        3        0        1        0        0        0        0
John          0        0        0        0        0        0        0        0        0        0        0        0        0
Tim           0        0        0        0        0        0        0        0        0        0        0        0        0

---

使用句点代替日期并转换为字符串....

x = {'John': 0,
 'Dan': 0,
 'Tim': 0,
 'Andrew': ['2022-04-10','2022-04-11','2022-06-16','2022-06-17','2022-06-18','2022-08-19','2022-08-20','2022-11-24','2022-12-12'],
 'Jack': ['2021-12-31','2022-01-01','2022-01-02','2022-03-26','2022-03-27','2022-03-28','2022-05-29','2022-06-01','2022-06-10','2022-06-12','2022-08-13']}

dfe = pd.DataFrame.from_dict(x, 'index').explode(0).set_axis(['dates'], axis=1).rename_axis('name').reset_index()

dfe['dates'] = pd.to_datetime(dfe['dates'], format='%Y-%m-%d').dt.to_period('M')

df_out = dfe.groupby(['name', 'dates']).size().unstack(fill_value=0)
df_out = df_out.drop('1970-01', axis=1)
df_out = df_out.reindex(pd.period_range(df_out.columns.min(), df_out.columns.max(), freq='M'), axis=1, fill_value=0)
print(df_out)

输出：

        2021-12  2022-01  2022-02  2022-03  2022-04  2022-05  2022-06  2022-07  2022-08  2022-09  2022-10  2022-11  2022-12
name                                                                                                                       
Andrew        0        0        0        0        2        0        3        0        2        0        0        1        1
Dan           0        0        0        0        0        0        0        0        0        0        0        0        0
Jack          1        2        0        3        0        1        3        0        1        0        0        0        0
John          0        0        0        0        0        0        0        0        0        0        0        0        0
Tim           0        0        0        0        0        0        0        0        0        0        0        0        0