【发布时间】:2015-04-19 10:11:29
【问题描述】:
使用以下代码,我可以正确地从 mysql db 接收动态列表并将元素放入列表视图中。
public class MenuActivity extends ListActivity implements FetchDataListener {
private ProgressDialog dialog;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_menu);
initView();
}
private void initView() {
// show progress dialog
dialog = ProgressDialog.show(this, "", "Loading..");
String url = "http://www.*********.php";
FetchDataTask task = new FetchDataTask(this);
task.execute(url);
}
@Override
public void onFetchComplete(List<Application> data) {
// dismiss the progress dialog
if(dialog != null) dialog.dismiss();
// create new adapter
ApplicationAdapter adapter = new ApplicationAdapter(this, data);
// set the adapter to list
setListAdapter(adapter);
}
@Override
public void onFetchFailure(String msg) {
// dismiss the progress dialog
if(dialog != null) dialog.dismiss();
// show failure message
Toast.makeText(this, msg, Toast.LENGTH_LONG).show();
}
这是我的数组适配器:
public class ApplicationAdapter extends ArrayAdapter<Application>{
private List<Application> items;
public ApplicationAdapter(Context context, List<Application> items) {
super(context, R.layout.app_cat_list, items);
this.items = items;
}
@Override
public int getCount() {
return items.size();
}
@Override
public View getView(int position, View convertView, ViewGroup parent) {
View v = convertView;
if(v == null) {
LayoutInflater li = LayoutInflater.from(getContext());
v = li.inflate(R.layout.app_cat_list, null);
}
Application app = items.get(position);
if(app != null) {
TextView titleText = (TextView)v.findViewById(R.id.titleTxt);
if(titleText != null) titleText.setText(app.getTitle());
}
return v;
}
现在我想单击单行并打开另一个通过 Intent extra 传递一些值的活动。 我应该在哪里实现点击监听器? 我很确定它应该插入到“getView”中,但我如何通过意图传递 app.getTitle()?我知道一般如何通过额外的意图,尝试但没有点击发生。 任何帮助将不胜感激,谢谢
【问题讨论】:
标签: android android-intent android-listview onclick android-arrayadapter