Android Studio：房间：错误：找不到字段的吸气剂答案

【问题标题】：Android Studio: Room: error: Cannot find getter for fieldAndroid Studio：房间：错误：找不到字段的吸气剂
【发布时间】：2020-02-24 08:38:31
【问题描述】：

我正在使用房间数据库进行本地缓存。在我的实体中，我有其他对象，它们的 getter 具有与其用途相关的接口的返回类型。但是房间找不到字段的吸气剂。我的目标是将这些接口用作返回类型，以便我可以将来自多个远程源的数据添加到一个数组中。如何在实现灵活和良好抽象的同时做到这一点？

public interface Venue {
  Location getLocation();
  Contact getContact();
}

public interface Location {
  double getLongitude();
  double getLatitude();
}

public interface Contact {
  String getPhoneNumber();
  String getFacebookUsername();
}

public class VenueSourceOne implements Venue{
   private VenueSourceOneLocation venueSourceOneLocation;
   private VenueSourceOneContact venueSourceOneContact;

   Location getLocation(){
      return venueSourceOneLocation;
   }

   Contact getContact(){
      return venueSourceOneContact
   }
}

public class VenueSourceTwo implements Venue{
   private VenueSourceTwoLocation venueSourceTwoLocation;
   private VenueSourceTwoContact venueSourceTwoContact;

   Location getLocation(){
      return venueSourceTwoLocation;
   }

   Contact getContact(){
      return venueSourceTwoContact
   }
}


public class Main{
   ....add to a List<Venue> and do something on the UI
}

【问题讨论】：

标签： android android-room

【解决方案1】：

出于我提出的问题以外的原因，我将场地接口更改为抽象类：

来自

public interface Venue {
  Location getLocation();
  Contact getContact();
}

到

public abstract class Venue {
      public abstract Location getLocation();
      public abstract Contact getContact();
}

我的问题的真正解决方案如下：

来自

public class VenueSourceOne implements Venue{
   private VenueSourceOneLocation venueSourceOneLocation;
   private VenueSourceOneContact venueSourceOneContact;

   Location getLocation(){
      return venueSourceOneLocation;
   }

   Contact getContact(){
      return venueSourceOneContact
   }
}

public class VenueSourceTwo implements Venue{
   private VenueSourceTwoLocation venueSourceTwoLocation;
   private VenueSourceTwoContact venueSourceTwoContact;

   Location getLocation(){
      return venueSourceTwoLocation;
   }

   Contact getContact(){
      return venueSourceTwoContact
   }
}

到

public class VenueSourceOne extends Venue{
   private VenueSourceOneLocation location;
   private VenueSourceOneContact contact;

   @Override
   VenueSourceOneLocation getLocation(){
      return location;
   }

   @Override
   VenueSourceOneContact getContact(){
      return contact;
   }
}

public class VenueSourceTwo extends Venue{
   private VenueSourceTwoLocation location;
   private VenueSourceTwoContact contact;

   @Override
   VenueSourceTwoLocation getLocation(){
      return location;
   }

   @Override
   VenueSourceTwoContact getContact(){
      return contact;
   }
}

列表在从源中检索数据时会使用抽象类指定的通用类型，而房间会使用特定类型存储数据。

【讨论】：