识别 json 文件中项目的位置答案

【问题标题】：Identify location of item in json file识别 json 文件中项目的位置
【发布时间】：2021-01-29 12:22:48
【问题描述】：

假设我有以下 json 文件。使用 data1["tenants"][1]['name'] 我可以选择 uniquename2。有没有办法通过遍历文档来收集“1”数字？

{
    "tenants": [{
            "key": "identifier",
            "name": "uniquename",
            "image": "url",
            "match": [
                "identifier"
            ],
            "tags": [
                "tag1",
                "tag2"
            ]
        },
        {
            "key": "identifier",
            "name": "uniquename2",
            "image": "url",
            "match": [
                "identifier1",
                "identifier2"
            ],
            "tags": ["tag"]
        }
    ]
}

简而言之：data1["tenants"][1]['name']= 唯一名称2 data1["tenants"][0]['name'] = 唯一名称我怎样才能找出哪个号码有哪个名字。那么如果我有 uniquename2 对应的数字/索引是什么？

【问题讨论】：

标签： python json dictionary indexing dictionary-comprehension

【解决方案1】：

您可以遍历租户以将索引映射到名称

data = {
    "tenants": [{
            "key": "identifier",
            "name": "uniquename",
            "image": "url",
            "match": [
                "identifier"
            ],
            "tags": [
                "tag1",
                "tag2"
            ]
        },
        {
            "key": "identifier",
            "name": "uniquename2",
            "image": "url",
            "match": [
                "identifier1",
                "identifier2"
            ],
            "tags": ["tag"]
        }
    ]
}

for index, tenant in enumerate(data['tenants']):
    print(index, tenant['name'])

输出

0 uniquename
1 uniquename2

【讨论】：

【解决方案2】：

假设您已经将 json 转换为字典，这就是您如何获取列表中第一次出现的名称的索引（这取决于名称实际上是唯一的）：

data = {
    "tenants": [{
            "key": "identifier",
            "name": "uniquename",
            "image": "url",
            "match": [
                "identifier"
            ],
            "tags": [
                "tag1",
                "tag2"
            ]
        },
        {
            "key": "identifier",
            "name": "uniquename2",
            "image": "url",
            "match": [
                "identifier1",
                "identifier2"
            ],
            "tags": ["tag"]
        }
    ]
}

def index_of(tenants, tenant_name):
    try:
        return tenants.index(
            next(
                tenant for tenant in tenants
                if tenant["name"] == tenant_name
            )
        )
    except StopIteration:
        raise ValueError(
            f"tenants list does not have tenant by name {tenant_name}."
        )

index_of(data["tenants"], "uniquename")  # 0

【讨论】：