TResponse 必须是具有无参数构造函数的非抽象类型才能将其用作参数 TResponse

Question

我正在尝试创建一个类似

的函数

        public static TResponse Run<TService, TResponse>(Controller mvcController,            IServiceController serviceController, Func<TService, TResponse> action, bool suppressErrors)
        where TService : ICommunicationObject
        where TResponse : ResponseBase<TResponse>
    {
        TResponse response = serviceController.Run<TService, TResponse>(action);
        if (!suppressErrors)
            response.Result.Errors.ToList().ForEach(i => mvcController.ModelState.AddModelError(UniqueKey.ValidationMessage, i.Message));
        return response;
    }

并且类被定义为

[DataContract]
public class ResponseBase<T> where T: new()
{
    public ResponseBase()
    {
        Result = new Result<T>();
    }

    [DataMember]
    public Result<T> Result { get; set; }
}

我收到编译错误，因为 TResponse 必须是具有无参数构造函数的非抽象类型才能将其用作参数 TResponse

任何帮助将不胜感激..

Answer 1

尽管您在ResponseBase<T> 中为T 定义了new() 约束，但编译器要求您在一般使用ResponseBase<T> 的其他类中声明相同的约束。

您所要做的就是在您的方法中将new() 约束添加到TResponse：

public static TResponse Run<TService, TResponse>(Controller mvcController, IServiceController serviceController, Func<TService, TResponse> action, bool suppressErrors)
    where TService : ICommunicationObject
    where TResponse : ResponseBase<TResponse>, new()