【发布时间】:2014-12-24 13:40:17
【问题描述】:
当我尝试按选定的索引值(在 IPython 会话中)过滤 DataFrame 时,我得到一个 NameError 异常。你可以看到valid 是numpy.array 而lab 是pandas.DataFrame 对象。它们都已初始化并可访问。但是我不能把它们放在一起。这是错误:
In [51]: valid
Out[51]:
array([38661, 44593, 38705, 38918, 38727, 38757, 38751, 38777, 38787,
...,
45328, 45337, 43645, 43694, 43701])
In [52]: lab
Out[52]:
0
39333 -1
39173 -1
42756 -1
39633 -1
38661 -1
44801 81
... ...
39379 -1
39742 -1
44765 108
44279 -1
40584 -1
41047 -1
41833 98
[3299 rows x 1 columns]
In [53]: lab[lab.index.map(lambda x: x in valid)]
---------------------------------------------------------------------------
NameError Traceback (most recent call last)
/home/vitaly/progs/vnii_gochs/venv/lib/python2.7/site-packages/django/core/management/commands/shell.pyc in <module>()
----> 1 lab[lab.index.map(lambda x: x in valid)]
/home/vitaly/progs/vnii_gochs/venv/lib/python2.7/site-packages/pandas/core/index.pyc in map(self, mapper)
1558
1559 def map(self, mapper):
-> 1560 return self._arrmap(self.values, mapper)
1561
1562 def isin(self, values, level=None):
/home/vitaly/progs/vnii_gochs/venv/lib/python2.7/site-packages/pandas/algos.so in pandas.algos.arrmap_int64 (pandas/algos.c:78469)()
/home/vitaly/progs/vnii_gochs/venv/lib/python2.7/site-packages/django/core/management/commands/shell.pyc in <lambda>(x)
----> 1 lab[lab.index.map(lambda x: x in valid)]
NameError: global name 'valid' is not defined
这段代码有什么问题?
【问题讨论】:
-
您能否添加一个我们可以运行的最小示例来重现您的错误?
-
@cel,我已经发布了指向带有对象转储文件的链接。
标签: python pandas namespaces ipython