ValueError：以 10 为底的 int() 的无效文字无法弄清楚原因

Question

我似乎无法弄清楚为什么当我运行我的程序时会收到错误 ValueError: invalid literal for int() with base 10: 'Enter pennies : '。 整个程序是由我的导师制作的，因此我们可以添加功能以使其正常工作。我目前正在尝试定义 get_input1 但我没有运气。任何帮助都会很棒。

def main():
    pennies = get_input1("Enter pennies : ")
    nickels = get_input("Enter nickels : ")
    dimes = get_input("Enter dimes : ")
    quarters = get_input("Enter quarters : ")

    print("You entered : ")
    print("\tPennies  : " , pennies)
    print("\tNickels  : " , nickels)
    print("\tDimes    : " , dimes)
    print("\tQuarters : " , quarters)


    total_value = get_total(pennies, nickels, dimes, quarters)
    dollars = get_dollars(pennies, nickels, dimes, quarters)
    left_over_cents = get_left_over_cents(pennies, nickels, dimes, quarters)

    print("Total = $", total_value, sep="")
    print("You have", dollars, "dollars and", left_over_cents, "cent(s)")

def get_input1(pennies):
    int(input("Enter Pennies: "))
    if int(pennies) < 0:
        print('Error: money cannot be negative')
        pennies = int(input('Enter correct amount of pennies: '))



main()

Answer 1

改变这个：

int(input("Enter Pennies: "))

到这里：

pennies = input("Enter Pennies: ")

已编辑 我相信这只是一个错字，您应该为输入结果分配便士。

Answer 2

def main():
    pennies = get_input1("Enter pennies : ")
    nickels = get_input2("Enter nickels : ")
    dimes = get_input3("Enter dimes : ")
    quarters = get_input4("Enter quarters : ")

    print("You entered : ")
    print("\tPennies  : " , pennies)
    print("\tNickels  : " , nickels)
    print("\tDimes    : " , dimes)
    print("\tQuarters : " , quarters)


    total_value = get_total(pennies, nickels, dimes, quarters)
    dollars = get_dollars(pennies, nickels, dimes, quarters)
    left_over_cents = get_left_over_cents(pennies, nickels, dimes, quarters)

    print("Total = $", total_value, sep="")
    print("You have", dollars, "dollars and", left_over_cents, "cent(s)")

def get_input1(pennies):
    pennies = int(input("Enter Pennies: "))
    if int(pennies) < 0:
        print('Error: money cannot be negative')
        pennies = int(input('Enter correct amount of pennies: '))

    return(pennies)

def get_input2(nickels):
    nickels = int(input("Enter nickels: "))
    if int(nickels) < 0:
        print('Error: money cannot be negative')
        pennies = int(input('Enter correct amount of nickels: '))

    return(nickels)

def get_input3(dimes):
    dimes = int(input("Enter dimes: "))
    if int(dimes) < 0:
        print('Error: money cannot be negative')
        pennies = int(input('Enter correct amount of dimes: '))

    return(dimes)

def get_input4(quarters):
    quarters = int(input("Enter quarters: "))
    if int(quarters) < 0:
        print('Error: money cannot be negative')
        pennies = int(input('Enter correct amount of quarters: '))

    return(quarters)

main()

这将帮助您定义您的便士、镍币、角钱和硬币。现在您必须定义 get_total、get_dollar 和 get_left_over_cents。

您需要在 int 值前面加上便士，这就是您收到错误的原因。然后你可以将硬币的价值返回给 main。

希望这会有所帮助！

Answer 3

您的数据流是反向的。在 main() 中，您调用 get_input1 来检索值，这与 input() 非常相似，但如果我们查看 get_input1 的作用：

# Names its argument, which was a question, "pennies"
def get_input1(pennies):
    # Asks a question, converts to int, and discards it
    int(input("Enter Pennies: "))
    if int(pennies) < 0:    # Converts pennies to int; but it was a question!
        print('Error: money cannot be negative')
        # This is the only place to alter pennies, but it doesn't return it
        pennies = int(input('Enter correct amount of pennies: '))

看起来这曾经是被重构以处理各种硬币的代码，每个硬币都有一个函数调用，但它没有它需要的两个修改：一种改变它要求的方法，以及一种方法返回答案。请注意，函数参数，如 get_input1 中的便士，是局部变量； main 永远不会看到它改变。