【发布时间】:2022-01-13 21:27:58
【问题描述】:
我正在尝试将这个小型 JavaScript websocket 应用程序转换为 Python 应用程序,以便我可以在树莓上运行它,但我就是想不通。这是我到目前为止所走的路,但我得到的只是“连接被拒绝”。我对 websockets 没有太多经验,所以我不知道从哪里开始
JavaScript:
let websocketClient
try {
websocketClient = new WebSocket("ws://127.0.0.1:15881/v2/feedbacks?app_id=123&app_name=hackvest")
} catch (e) {
console.log("PlayerSocket", e)
}
websocketClient.onopen = function() {
console.log("open");
};
websocketClient.onmessage = function(e) {
websocketClient.send(JSON.stringify({
"Submit": [{
"Type": "turnOff",
"Key": ""
}]
}));
console.log(e)
};
websocketClient.onclose = function(e) {
console.log("close");
console.log(e)
};
var n = JSON.stringify({
Submit: [{
Type: "turnOff",
Key: ""
}]
})
Python:
import websocket
import _thread
import time
def on_message(ws, message):
print(message)
def on_error(ws, error):
print(error)
def on_close(ws, close_status_code, close_msg):
print("### closed ###")
def on_open(ws):
print("open")
if __name__ == "__main__":
websocket.enableTrace(True)
ws = websocket.create_connection("ws://127.0.0.1:15881/v2/feedbacks?app_id=com.bhaptics.designer2&app_name=hackvest",
on_open=on_open,
on_message=on_message,
on_error=on_error,
on_close=on_close)
ws.run_forever()
【问题讨论】:
-
请澄清您的具体问题或提供其他详细信息以准确突出您的需求。正如目前所写的那样,很难准确地说出你在问什么。
标签: javascript python websocket