Flask wtforms AttributeError：“HTMLString”对象没有属性“分页”

Question

有人在这里帮我写了一些很棒的代码，用一个提交按钮多次显示同一个表单，这很有效，但是由于我需要为页面分页的表单有数百个，所以我已经能够过去对页面进行分页，但我不知道如何在 for 循环中使用该代码和表单。 这是我的代码：（在 Greg 的大力帮助下）

@bp.route('/stock', methods=['GET', 'POST'])
@bp.route('/stock/stock/', methods=['GET', 'POST'])
@login_required
def stock():
    stocks = Stock.query.all()
    forms = []
    for stock in stocks:
        form = AddStockForm()
        form.id.default = stock.id
        form.image.default = stock.image_url
        form.date.default = stock.date
        form.description.default = stock.description
        form.event.default = stock.event
        form.achat.default = stock.achat
        form.vente.default = stock.vente
        form.sold.default = stock.sold
        forms.append(form)

    for form in forms:
        if form.validate_on_submit():
            if form.modify.data:
                stock = Stock.query.filter_by(id=form.id.data).one()
                stock.date = form.date.data
                stock.description = form.description.data
                stock.event = form.event.data
                stock.achat = form.achat.data
                stock.vente = form.vente.data
                stock.sold = form.sold.data
                db.session.add(stock)
                db.session.commit()
            elif form.delete.data:
                stock = Stock.query.filter_by(id=form.id.data).one()
                db.session.delete(stock)
                db.session.commit()
            return redirect(url_for('stock.stock'))

        form.process()  # Do this after validate_on_submit or breaks CSRF token
        page = request.args.get('page', 1, type=int)
        forms = forms[1].id().paginate(
             page, current_app.config['ITEMS_PER_PAGE'], False)
        next_url = url_for('stock.stock', page=forms.next_num) \
            if forms.has_next else None
        prev_url = url_for('stock.stock', page=forms.prev_num) \
            if forms.has_prev else None
    return render_template('stock/stock.html',forms=forms.items, title=Stock, stocks=stocks)

我正在尝试使用“表单”是一个列表来对结果进行分页这一事实，我显然不明白如何做到这一点，我看过flask-paginate，但我也不明白！ 非常需要所有帮助 热烈的问候，保罗。

编辑 我尝试使用flask_pagination，这是我的代码：

@bp.route('/stock/stock/', methods=['GET', 'POST'])
@login_required
def stock():
    search = False
    q = request.args.get('q')
    if q:
        search = True
    page = request.args.get(get_page_parameter(), type=int, default=1)
    stocks = Stock.query.all()
    forms = []
  #rest of code here#
        pagination = Pagination(page=page, total=stocks.count(), search=search, record_name='forms')
        form.process()  # Do this after validate_on_submit or breaks CSRF token
   return render_template('stock/stock.html',forms=forms, title=Stock, pagination=pagination)

这给出了一个不同的错误“TypeError：count() 只接受一个参数（给定 0）”我也尝试使用“total=forms.count()”并得到了同样的错误！

Answer 1

我讨厌这样做，因为它在开始时表现出缺乏耐心，但这个答案可能对其他人有所帮助，我通过两种方式解决了我的问题，第一种是决定显示顺序（降序或升序）的查询，然后允许我使用flask-paginate在几页上显示结果，我意识到我正在处理一个列表，其中一位开发人员link的示例向我展示了方法，这是我的代码，

from flask_paginate import Pagination, get_page_args


@bp.route('/stock', methods=['GET', 'POST'])
@bp.route('/stock/stock/', methods=['GET', 'POST'])
@login_required
def stock():
    stocks = Stock.query.order_by(Stock.id.desc())# this gives order of results
    forms = []
    def get_forms(offset=0, per_page=25): #this function sets up the number of
        return forms[offset: offset + per_page]  #results per page
for stock in stocks:
    form = AddStockForm()
    form.id.default = stock.id
    form.image.default = stock.image_url
    form.date.default = stock.date
    form.description.default = stock.description
    form.event.default = stock.event
    form.achat.default = stock.achat
    form.vente.default = stock.vente
    form.sold.default = stock.sold
    forms.append(form)
for form in forms:
    if form.validate_on_submit():
        if form.modify.data:
            stock = Stock.query.filter_by(id=form.id.data).one()
            stock.date = form.date.data
            stock.description = form.description.data
            stock.event = form.event.data
            stock.achat = form.achat.data
            stock.vente = form.vente.data
            stock.sold = form.sold.data
            db.session.add(stock)
            db.session.commit()
        elif form.delete.data:
            stock = Stock.query.filter_by(id=form.id.data).one()
            db.session.delete(stock)
            db.session.commit()
        return redirect(url_for('stock.stock'))

    #this is the code from the link that I used to paginate
    page, per_page, offset = get_page_args(page_parameter='page',
                                           per_page_parameter='per_page')
    total = len(forms) # this code counts the resulting list to be displayed
    pagination_forms = get_forms(offset=offset, per_page=per_page)
    pagination = Pagination(page=page, per_page=per_page, total=total)
    form.process()  # Do this after validate_on_submit or breaks CSRF token

return render_template('stock/stock.html', title=Stock, stocks=stocks
                       page=page, forms=pagination_forms, per_page=per_page, pagination=pagination)
#And finally this is the pagination passed to the html

所以这对于所有像我这样挣扎但仍然热爱它的笨蛋。