使用 python selenium 关闭每 30 秒打开的每个 webdriver

Question

嘿，我想连续执行多个浏览器，但是当每个浏览器打开时，每个浏览器应该每 30 秒关闭一次

import time
from selenium import webdriver
from webdriver_manager.chrome import ChromeDriverManager


with open('configure.txt','r') as f:
  config = f.readlines()
  l= config[0].strip('\n').split('|')[1].strip(' ')
  print(l)
  # 2nd line
  t = config[1].strip('\n').split('|')[1].strip(' ')
  print(t)
with open('proxies.txt','r') as f:
i=f.readline()
def web():
  print(i)
  option.add_argument('--proxy-server=%s' % i)
  driver = webdriver.Chrome(ChromeDriverManager().install(), options=option)
  driver.execute_script(f'''window.open("{l}","_blank");''')
  time.sleep(2)
  driver.close()
  time.sleep(30)
  driver.quit()





 for i in range(0,5):
   web()

Answer 1

您绝对可以为此使用多线程，但我建议您至少查看asyncio。而不是手动生成线程并 wait()'ing 让它们完成。您可以在事件循环上安排事件。下面是一个小代码示例来说明您的用例。

from selenium import webdriver
from webdriver_manager.chrome import ChromeDriverManager
import asyncio
import random


async def open_and_close():
    driver = webdriver.Chrome(ChromeDriverManager().install())
    driver.execute_script(f"""window.open("{"http://google.com"}","_blank");""")
    await asyncio.sleep(2)
    driver.close()
    await asyncio.sleep(random.randint(0, 10))
    driver.quit()


async def main():
    # Schedule multiple browser actions *concurrently*:
    funcs = [open_and_close() for i in range(5)]

    L = await asyncio.gather(*funcs)


asyncio.run(main())