使用 Google Places API 删除 GPS 请求周围的多余字符

Question

See here for a working example of my Google Sheet

Here is my Google Apps Script

---

我有一个用于旅行的副项目which I have been working on for some time。它利用 Google Places API 来提取有关地点的相关数据并将其记录在 Google Sheet 中。从那里，我将工作表导入到 Google MyMap 中，这会在 Google 地图上创建一个叠加层，我可以使用它来快速导航和查找信息。

我正在尝试为要填写工作表的各个字段创建单独的函数。所以会有营业时间、地址、谷歌地图链接、营业网站等单独的功能。

当涉及到 GPS 坐标时，坐标会返回到地点的几何图形和位置子部分中。

BIG Alice Brewing 的Here is an example：

{
   "html_attributions" : [],
   "result" : {
      "formatted_address" : "8-08 43rd Rd, Long Island City, NY 11101, USA",
      "formatted_phone_number" : "(347) 688-2337",
      "geometry" : {
         "location" : {
            "lat" : 40.75208620000001,
            "lng" : -73.9505873
         },
         "viewport" : {
            "northeast" : {
               "lat" : 40.75347488029151,
               "lng" : -73.94919081970849
            },
            "southwest" : {
               "lat" : 40.75077691970851,
               "lng" : -73.9518887802915
            }
         }
      },
      "name" : "Big aLICe Brewing",
      "opening_hours" : {
         "open_now" : true,
         "periods" : [
            {
               "close" : {
                  "day" : 0,
                  "time" : "2000"
               },
               "open" : {
                  "day" : 0,
                  "time" : "1200"
               }
            },
            {
               "close" : {
                  "day" : 1,
                  "time" : "2100"
               },
               "open" : {
                  "day" : 1,
                  "time" : "1600"
               }
            },
            {
               "close" : {
                  "day" : 2,
                  "time" : "2100"
               },
               "open" : {
                  "day" : 2,
                  "time" : "1600"
               }
            },
            {
               "close" : {
                  "day" : 3,
                  "time" : "2100"
               },
               "open" : {
                  "day" : 3,
                  "time" : "1600"
               }
            },
            {
               "close" : {
                  "day" : 4,
                  "time" : "2100"
               },
               "open" : {
                  "day" : 4,
                  "time" : "1600"
               }
            },
            {
               "close" : {
                  "day" : 5,
                  "time" : "2200"
               },
               "open" : {
                  "day" : 5,
                  "time" : "1200"
               }
            },
            {
               "close" : {
                  "day" : 6,
                  "time" : "2200"
               },
               "open" : {
                  "day" : 6,
                  "time" : "1200"
               }
            }
         ],
         "weekday_text" : [
            "Monday: 4:00 – 9:00 PM",
            "Tuesday: 4:00 – 9:00 PM",
            "Wednesday: 4:00 – 9:00 PM",
            "Thursday: 4:00 – 9:00 PM",
            "Friday: 12:00 – 10:00 PM",
            "Saturday: 12:00 – 10:00 PM",
            "Sunday: 12:00 – 8:00 PM"
         ]
      },
      "types" : [ "food", "point_of_interest", "establishment" ],
      "url" : "https://maps.google.com/?cid=10003627310223249349",
      "website" : "http://bigalicebrewing.com/"
   },
   "status" : "OK"
}

如果我只想返回 40.75208620000001, -73.9505873 的 GPS 坐标，我需要做什么才能返回该值而无需额外的

`"lat" : 40.75208620000001,
            "lng" : -73.9505873`

部分价值？

以下是我如何返回其余值的工作代码：

// This location basis is used to narrow the search -- e.g. if you were
// building a sheet of bars in NYC, you would want to set it to coordinates
// in NYC.
// You can get this from the url of a Google Maps search.
const LOC_BASIS_LAT_LON = "40.754734421655655, -73.98840133506883"; // e.g. "37.7644856,-122.4472203"

function COMBINED2(text) {
  var API_KEY = 'AIzxxxxxxxxxxxxxxxxxxxlrE';
  var baseUrl = 'https://maps.googleapis.com/maps/api/place/findplacefromtext/json';
  var queryUrl = baseUrl + '?input=' + text + '&inputtype=textquery&key=' + API_KEY + "&locationbias=point:" + LOC_BASIS_LAT_LON;
  var response = UrlFetchApp.fetch(queryUrl);
  var json = response.getContentText();
  var placeId = JSON.parse(json);
  var ID = placeId.candidates[0].place_id;

  var fields = 'name,formatted_address,formatted_phone_number,website,url,types,opening_hours';
  var baseUrl2 = 'https://maps.googleapis.com/maps/api/place/details/json?placeid=';
  var queryUrl2 = baseUrl2 + ID + '&fields=' + fields + '&key='+ API_KEY + "&locationbias=point:" + LOC_BASIS_LAT_LON;

  if (ID == '') {
    return 'Give me a Google Places URL...';
  }

  var response2 = UrlFetchApp.fetch(queryUrl2);
  var json2 = response2.getContentText();
  var place = JSON.parse(json2).result;

  var placeName = place.name;
  var placeAddress = place.formatted_address;
  var placePhoneNumber = place.formatted_phone_number;
  var placeWebsite = place.website;
  var placeURL = place.url;

  var weekdays = '';
  place.opening_hours.weekday_text.forEach((weekdayText) => {
    weekdays += ( weekdayText + '\r\n' );
  } );


  var data = [ [
    place.name,
    place.formatted_address,
    place.formatted_phone_number,
    place.website,
    place.url,
    weekdays.trim()
  ] ];

  return data;
}

---

完成的代码

我设法将 Irvin 的代码合并如下。

    function GPS(text) {

   //TEST PARSING
     var API_KEY = 'AIzaSxxxxxxxxxxxxxxxxxxxx';
    var baseUrl = 'https://maps.googleapis.com/maps/api/place/findplacefromtext/json';
    var queryUrl = baseUrl + '?input=' + text + '&inputtype=textquery&key=' + API_KEY + "&locationbias=point:" + LOC_BASIS_LAT_LON;
    var response = UrlFetchApp.fetch(queryUrl);
    var json = response.getContentText();
    var placeId = JSON.parse(json);
    var ID = placeId.candidates[0].place_id;

    var fields = 'name,geometry,formatted_address,formatted_phone_number,website,url,types,opening_hours';
    var baseUrl2 = 'https://maps.googleapis.com/maps/api/place/details/json?placeid=';
    var queryUrl2 = baseUrl2 + ID + '&fields=' + fields + '&key='+ API_KEY + "&locationbias=point:" + LOC_BASIS_LAT_LON;
    
    var responseAPI = UrlFetchApp.fetch(queryUrl2); 
    var content = responseAPI.getContentText();
    var json = JSON.parse(content.toString()); //Sample JSON parsing

    //An array variable to contain the longitude and latitude data
    var inputArray = []; 
    //Parse the "location" JSON array contents
    var gpsCoord = json.result.geometry.location

    //Place the JSON contents into the array variable
    for (var j in gpsCoord){ 
      inputArray.push([gpsCoord[j]]); 
    }
    return inputArray.join(", "); 


}

Answer 1

建议

您可以尝试将“result.geometry.location”的 JSON 数组值放入您的 Apps 脚本代码的数组变量中。您可以参考下面的示例脚本，然后相应地调整您的脚本：

示例脚本：

 function gpsCoordinate() {
    //TEST PARSING
    var responseAPI = UrlFetchApp.fetch("https://maps.googleapis.com/maps/api/place/details/json?placeid=ChIJh9-J99hYwokRxc9AgwkG1Io&fields=name,formatted_address,geometry,formatted_phone_number,website,url,types,opening_hours&key=AIzaSyD1FOrIRLbO9mV4zbh6df0os6ZCeaGKlrE&locationbias=point:42.6408341747088,18.109130742689384"); 
    var content = responseAPI.getContentText();
    var json = JSON.parse(content.toString()); //Sample JSON parsing

    //An array variable to contain the longitude and latitude data
    var inputArray = []; 
    //Parse the "location" JSON array contents
    var gpsCoord = json.result.geometry.location

    //Place the JSON contents into the array variable
    for (var j in gpsCoord){ 
      inputArray.push([gpsCoord[j]]); 
    }
    return inputArray; 
  }

注意：使用Google Apps Script to Output a JSON Array into a row中的代码作为参考

样本结果：

gpsCoordinate() 方法只返回 JSON 结果中的经纬度值：