【发布时间】:2016-03-04 18:43:41
【问题描述】:
我是从网上得到的。
// <script src="https://maps.googleapis.com/maps/api/js?key=YOUR_API_KEY&libraries=places">
var map;
var infowindow;
function initMap() {
var pyrmont = {lat: -33.867, lng: 151.195};
map = new google.maps.Map(document.getElementById('map'), {
center: pyrmont,
zoom: 15
});
infowindow = new google.maps.InfoWindow();
var service = new google.maps.places.PlacesService(map);
service.nearbySearch({
location: pyrmont,
radius: 500,
type: ['store']
}, callback);
}
function callback(results, status) {
if (status === google.maps.places.PlacesServiceStatus.OK) {
for (var i = 0; i < results.length; i++) {
createMarker(results[i]);
}
}
}
function createMarker(place) {
var placeLoc = place.geometry.location;
var marker = new google.maps.Marker({
map: map,
position: place.geometry.location
});
google.maps.event.addListener(marker, 'click', function() {
infowindow.setContent(place.name);
infowindow.open(map, this);
});
}
如何搜索半径为 5 英里的自定义位置,例如 CVS 药店而不是商店?也可以提供附近搜索的全套属性的参考吗?
【问题讨论】:
标签: javascript google-maps google-places-api