如何获取活跃员工的数量（所有月份）答案

【问题标题】：How to Get count of active employees (in all months)如何获取活跃员工的数量（所有月份）
【发布时间】：2019-07-14 14:14:51
【问题描述】：

我正在尝试在（Fusion BI 报告）中创建 HCM 报告，以检索所选年份“所有月份”的员工人数。

在当前情况下，当我们运行“2017”报告时，它会检索 7 月、8 月、9 月的员工总数

需要什么：当参数 = '2017' AND 9 月之后的月份为 null 时，获取最后一个存在的值，即 'Sept' 中的值

Month Name   Current result    Expected result
July          1                 1
Aug           3                 3 
Sept          4                 4
Oct                             4
Nov                             4
Dec                             4

我的查询

SELECT PIVOT_TBL.* FROM
(SELECT
        COUNT(PAPF.PERSON_ID) OVER (ORDER BY  TO_CHAR(PAPF.START_DATE,'MM-YYYY')) AS OP_BALANCE,
        EXTRACT (MONTH FROM PAPF.START_DATE)  AS OMONTHS


 FROM
        PER_ALL_PEOPLE_F          PAPF,
        PER_ALL_ASSIGNMENTS_M     PAAM,   
        PER_PERSONS               PP  

WHERE     
        PAAM.PERSON_ID              =  PAPF.PERSON_ID
    AND PP.PERSON_ID                =  PAPF.PERSON_ID  
    ------------------------------------------------ 
    AND PAAM.ASSIGNMENT_TYPE        =  'E'
    AND PAAM.PRIMARY_FLAG           =  'Y'  
    AND PAAM.EFFECTIVE_LATEST_CHANGE = 'Y' 
    AND PAAM.ASSIGNMENT_STATUS_TYPE  = 'ACTIVE'
    -------------------------------------------------
    AND TRUNC(SYSDATE) BETWEEN PAPF.EFFECTIVE_START_DATE    AND  PAPF.EFFECTIVE_END_DATE 
    AND TRUNC(SYSDATE) BETWEEN PAAM.EFFECTIVE_START_DATE    AND  PAAM.EFFECTIVE_END_DATE  
    AND TO_CHAR(PAPF.START_DATE,'YYYY')='2017'
    ORDER BY 2)SRC_TABLE

    PIVOT
    (MAX(OP_BALANCE) AS EJ FOR OMONTHS IN
    ('1' AS JAN , '2' AS FEB , '3' AS MAR , '4'  AS APR , '5'  AS MAY , '6'  AS JUNE ,
     '7' AS JUL , '8' AS AUG , '9' AS SEPT, '10' AS OCTO, '11' AS NOV , '12' AS DECE)
    )PIVOT_TBL

【问题讨论】：

标签： sql oracle fusion

【解决方案1】：

您必须以某种方式确保所有月份都存在，然后使用 LAST_VALUE() 函数和 IGNORE NULLS 将最后一个非空值复制到后面的月份。

var yr number;
exec :yr := 2017;
with raw_results(dte, rslt) as (
  select date '2017-07-01', 1 from dual union all
  select date '2017-08-01', 3 from dual union all
  select date '2017-09-01', 4 from dual
)
, min_dte as (
  select min(dte) dte from raw_results
  where dte >= trunc(to_date(:yr,'yyyy'), 'yy')
)
, months as (
  select add_months(dte, level-1) dte
  from min_dte
  connect by extract(year from add_months(dte, level-1)) = :yr
)
select to_char(dte, 'Mon') "Month", 
  last_value(rslt ignore nulls) over(order by dte) "Result"
from months
left join raw_results using(dte);

Month            Result
------------ ----------
Jul                   1
Aug                   3
Sep                   4
Oct                   4
Nov                   4
Dec                   4

【讨论】：

错误：SQL 查询时间超过限制 (500)。已停止处理。
很好的解决方案。

【解决方案2】：

通过提取连接（年份来自 add_months(dte, level-1)) = :yr ) 选择 to_char(dte, 'Mon') "月", last_value(rslt 忽略空值) over(order by dte) "Result" 从几个月 left join raw_results using(dte);

月份结果

7 月 1 日 8 月 3 日 9月4日 10 月 4 日 11 月 4 日 12 月 4 日

【讨论】：