【发布时间】：2013-08-20 22:18:21
【问题描述】：
问题
我一直在尝试让this google maps API 示例正常工作，但在从 google 网站完全复制代码后，该示例无法正确呈现。即地图完全无法渲染，搜索栏是页面等的-350px。
要了解我的意思，请查看JSfiddle。
该示例在 Google 的上述文档页面上运行良好，所以我知道我正在做的事情。有什么想法吗？
编辑：我从 google 的网站获得了 css，但问题仍然存在。
以下是导致问题的代码：
<!DOCTYPE html>
<html>
<head>
<title>Places Autocomplete</title>
<meta name="viewport" content="initial-scale=1.0, user-scalable=no">
<meta charset="utf-8">
<link href="CSS/default.css" rel="stylesheet">
<script src="https://maps.googleapis.com/maps/api/js?v=3.exp&sensor=false&libraries=places"></script>
<style>
input {
border: 1px solid rgba(0, 0, 0, 0.5);
}
input.notfound {
border: 2px solid rgba(255, 0, 0, 0.4);
}
</style>
<script>
function initialize() {
var mapOptions = {
center: new google.maps.LatLng(-33.8688, 151.2195),
zoom: 13,
mapTypeId: google.maps.MapTypeId.ROADMAP
};
var map = new google.maps.Map(document.getElementById('map-canvas'),
mapOptions);
var input = /** @type {HTMLInputElement} */(document.getElementById('searchTextField'));
var autocomplete = new google.maps.places.Autocomplete(input);
autocomplete.bindTo('bounds', map);
var infowindow = new google.maps.InfoWindow();
var marker = new google.maps.Marker({
map: map
});
google.maps.event.addListener(autocomplete, 'place_changed', function() {
infowindow.close();
marker.setVisible(false);
input.className = '';
var place = autocomplete.getPlace();
if (!place.geometry) {
// Inform the user that the place was not found and return.
input.className = 'notfound';
return;
}
// If the place has a geometry, then present it on a map.
if (place.geometry.viewport) {
map.fitBounds(place.geometry.viewport);
} else {
map.setCenter(place.geometry.location);
map.setZoom(17); // Why 17? Because it looks good.
}
marker.setIcon(/** @type {google.maps.Icon} */({
url: place.icon,
size: new google.maps.Size(71, 71),
origin: new google.maps.Point(0, 0),
anchor: new google.maps.Point(17, 34),
scaledSize: new google.maps.Size(35, 35)
}));
marker.setPosition(place.geometry.location);
marker.setVisible(true);
var address = '';
if (place.address_components) {
address = [
(place.address_components[0] && place.address_components[0].short_name || ''),
(place.address_components[1] && place.address_components[1].short_name || ''),
(place.address_components[2] && place.address_components[2].short_name || '')
].join(' ');
}
infowindow.setContent('<div><strong>' + place.name + '</strong><br>' + address);
infowindow.open(map, marker);
});
// Sets a listener on a radio button to change the filter type on Places
// Autocomplete.
function setupClickListener(id, types) {
var radioButton = document.getElementById(id);
google.maps.event.addDomListener(radioButton, 'click', function() {
autocomplete.setTypes(types);
});
}
setupClickListener('changetype-all', []);
setupClickListener('changetype-establishment', ['establishment']);
setupClickListener('changetype-geocode', ['geocode']);
}
google.maps.event.addDomListener(window, 'load', initialize);
</script>
</head>
<body>
<div id="panel" style="margin-left: -260px">
<input id="searchTextField" type="text" size="50">
<input type="radio" name="type" id="changetype-all" checked="checked">
<label for="changetype-all">All</label>
<input type="radio" name="type" id="changetype-establishment">
<label for="changetype-establishment">Establishments</label>
<input type="radio" name="type" id="changetype-geocode">
<label for="changetype-geocode">Geocodes</lable>
</div>
<div id="map-canvas"></div>
</body>
</html>
【问题讨论】：
-
你也需要css。
-
@geocodezip 谢谢，我已经用网站上包含的 css 更新了小提琴。它更好，但仍然无法正确呈现，现在搜索栏的功能丢失了。
-
@geocodezip 谢谢，代码在小提琴中失败，但在我的本地机器上工作。感谢您的帮助
标签： javascript html google-maps google-maps-api-3