【发布时间】:2019-07-23 12:45:43
【问题描述】:
我是这个Flutter的新手
我正在尝试更改 FlatButton 文本,而 onPressed。我的页面设计在单独的Widget 方法中,所以无法在onPressed 中添加setState()。
我搜索了很多。但是,没找到。请帮我解决这个问题。
import 'package:flutter/material.dart';
int number = 10;
class SecondRoute extends StatelessWidget {
Widget build(BuildContext context) {
return new Scaffold(
appBar: new AppBar(
title: new Text('Lists'),
backgroundColor: new Color(0xFF000000),
),
body: DynamicChange(),
);
}
}
class DynamicChange extends StatefulWidget {
@override
StateDynamic createState() => StateDynamic();
} // Class SecondRoute
class StateDynamic extends State<DynamicChange> {
Widget build(BuildContext context) {
return new Scaffold(
body: thisScreenNeeds(),
);
}
}
Widget thisScreenNeeds() {
return Container(
margin: EdgeInsets.only(top: 100, left: 50),
child: FlatButton(
child: Text(
number.toString(),
textAlign: TextAlign.center,
style: (TextStyle(
fontWeight: FontWeight.bold, fontSize: 60, color: Colors.green)),
),
onPressed: () {
// Unable to add, setState(). Throwing error.
},
));
}
尝试 1
onPressed: () {
// Error: The member 'setState' can only be used within instance members of subclasses
StateDynamic().setState(() {
number = number + 1;
});
},
尝试 2
class StateDynamic extends State<DynamicChange> {
.....
.........
void _incrementCounter() {
setState(() {
number++;
});
}
.....
.......
}
onPressed: StateDynamic()._incrementCounter,
// Run Time Error:
This happens when you call setState() on a State object for a
widget that hasn't been inserted into the widget tree yet.
It is not necessary to call setState() in the constructor,
since the state is already assumed to be dirty when it is
initially created.
【问题讨论】:
标签: flutter dart flutter-layout