如何在颤动中解析 PurpleAir JSON？

Question

所以我正在尝试从 here 解析 PurpleAir JSON。

使用this documentation。

我无法访问我真正想要的数据，例如实时 2.5 AQI 读数。

这是我的代码，它以字符串形式返回解析的 JSON 数据，我能得到的只是地图版本，有人能告诉我如何修改这段代码来获取其他数据吗？（基本上，我应该输入什么jsonResponse 括号以获取标记为 /v./) 的元素

Future<String> sensorTest() async{
  var url = "https://www.purpleair.com/json?show=15130";
  var response =  await http.get(url);//Parses it
   if (response.statusCode == 200){
      var jsonResponse = convert.jsonDecode(response.body);
      var aqi = jsonResponse['mapVersion']; 
      String output = "Map Version: "+aqi;
      return output;
   }
   else{
     return "Something is wrong";
   }    
}

Answer 1

我重构代码以使其更具可读性，它对我有用，我得到了print：

地图版本：0.72

import 'dart:convert';
import 'package:http/http.dart' as http;

Future<String> sensorTest() async {
    const String url = 'https://www.purpleair.com/json?show=15130';
    final http.Response response = await http.get(url);
    if (response.statusCode == 200) {
      final dynamic jsonResponse = jsonDecode(response.body);
      final dynamic aqi = jsonResponse['mapVersion'];
      final String output = 'Map Version: $aqi';
      print(output);
      return output;
    } else
      return 'Something is wrong';
  }

为了得到v，你可以这样做：

import 'dart:convert';
import 'package:http/http.dart' as http;

Future<String> sensorTest() async {
    const String url = 'https://www.purpleair.com/json?show=15130';
    final http.Response response = await http.get(url);
    if (response.statusCode == 200) {
      final dynamic jsonResponse = jsonDecode(response.body);
      final dynamic aqi = jsonResponse['results'][0]['Stats']['v'];
      final String v = 'V: $aqi';
      print(v);
      return v;
    } else
      return 'Something is wrong';
  }