【发布时间】:2019-03-22 13:17:24
【问题描述】:
我的项目中有两个活动,一个是 MainActivity,另一个是 Main2activity,在 Main2activity 中,我从用户那里获取输入并将其存储在 SharedPreference 中,现在我想将此数据传递给 MainActivity 并将该数据显示给用户。
Main2activity的代码是
package com.example.to_doapp;
import android.content.Context;
import android.content.Intent;
import android.content.SharedPreferences;
import android.os.Bundle;
import android.support.design.widget.FloatingActionButton;
import android.support.design.widget.Snackbar;
import android.support.v7.app.AppCompatActivity;
import android.support.v7.widget.Toolbar;
import android.view.View;
import android.widget.EditText;
import java.io.Serializable;
import java.util.ArrayList;
public class Main2Activity extends AppCompatActivity {
public void BackMain ( View view )
{
Intent intent = new Intent( getApplicationContext() ,MainActivity.class ) ;
SharedPreferences sharedPreferences = this.getSharedPreferences( "com.example.to_doapp;", Context.MODE_PRIVATE);
EditText editText = ( EditText) findViewById( R.id.editText3) ;
String s = editText.getText().toString();
sharedPreferences.edit().putString("task" , s ) .apply();
//intent.putStringArrayListExtra("key",arr);
startActivity(intent);
}
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main2);
Toolbar toolbar = findViewById(R.id.toolbar);
setSupportActionBar(toolbar);
FloatingActionButton fab = findViewById(R.id.fab);
fab.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View view) {
Snackbar.make(view, "Replace with your own action", Snackbar.LENGTH_LONG)
.setAction("Action", null).show();
}
});
}
}
代码敌人 Mainactivity 是
package com.example.to_doapp;
import android.content.Intent;
import android.os.Bundle;
import android.support.design.widget.FloatingActionButton;
import android.support.design.widget.Snackbar;
import android.support.v7.app.AppCompatActivity;
import android.support.v7.widget.Toolbar;
import android.view.View;
import android.view.Menu;
import android.view.MenuItem;
import android.widget.LinearLayout;
import android.widget.TextView;
import android.widget.Toast;
import java.io.Serializable;
import java.util.ArrayList;
public class MainActivity extends AppCompatActivity {
public void onclick (View view){
Intent intent = new Intent(getApplicationContext(), Main2Activity.class );
startActivity(intent);
}
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
Toolbar toolbar = findViewById(R.id.toolbar);
setSupportActionBar(toolbar);
FloatingActionButton fab = findViewById(R.id.fab);
fab.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View view) {
Snackbar.make(view, "Replace with your own action", Snackbar.LENGTH_LONG)
.setAction("Action", null).show();
}
});
Intent intent = getIntent();
}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
// Inflate the menu; this adds items to the action bar if it is present.
getMenuInflater().inflate(R.menu.menu_main, menu);
return true;
}
@Override
public boolean onOptionsItemSelected(MenuItem item) {
// Handle action bar item clicks here. The action bar will
// automatically handle clicks on the Home/Up button, so long
// as you specify a parent activity in AndroidManifest.xml.
int id = item.getItemId();
//noinspection SimplifiableIfStatement
if (id == R.id.action_settings) {
return true;
}
return super.onOptionsItemSelected(item);
}
}
我想知道如何传递共享首选项以及如何在列表视图中向用户显示该数据。 提前感谢您的帮助。
【问题讨论】:
-
无需将 SharedPreference 从一个屏幕传递到另一个屏幕,因为您可以通过按键从应用程序的任何位置访问 SharedPreference 对象。
-
@RutvikBhatt 请详细说明!!由于我是新手,我无法理解。
-
@swati 我听不懂!!span>
标签: android android-intent sharedpreferences