【发布时间】:2015-03-10 19:33:56
【问题描述】:
我正在开发我的第一个 android 应用程序,我的主要活动上有一个微调器,当用户在登陆屏幕或活动之后在那里运行应用程序时,将是基于不同的(不是主要的)。我将来自微调器的选择存储在共享首选项中,如果已设置,我想在启动时加载不同的活动。
代码
private Spinner spinner;
private SharedPreferences favTeam;
//private SharedPreferences.Editor editor;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
/*
if (favTeam.contains("team") && favTeam != null) {
Intent intent = new Intent(this, MyTeamActivity.class);
startActivity(intent);
} else {
System.out.println("-------- cant read from shared pref -----------");
}
*/
spinner = (Spinner) findViewById(R.id.selectTeam);
ArrayAdapter<CharSequence> adapter = ArrayAdapter.createFromResource(this, R.array.teams_array, android.R.layout.simple_spinner_item);
adapter.setDropDownViewResource(android.R.layout.simple_spinner_dropdown_item);
spinner.setAdapter(adapter);
}
public void submitMyTeam(View v){
favTeam = this.getSharedPreferences("com.lonerganonline.league_of_ireland", Context.MODE_PRIVATE);
//SharedPreferences favTeam = this.getSharedPreferences("com.lonerganonline.league_of_ireland", Context.MODE_PRIVATE);
TextView txt = (TextView) findViewById(R.id.textView);
String selectedTeam = spinner.getSelectedItem().toString();
SharedPreferences.Editor editor = favTeam.edit();
editor.putString("team", selectedTeam);
editor.apply();
Intent intent = new Intent(this, MyTeamActivity.class);
txt.setText(favTeam.getString("team","Not Defined"));
startActivity(intent);
}
我尝试通过上面代码中注释掉的 if 语句来执行此操作,但这导致了致命错误。 任何帮助将不胜感激。
【问题讨论】:
标签: android android-activity sharedpreferences if-this-then-that